jewlzme17
  • jewlzme17
Find the value x such that f(x)=0, if f(x)=(3x-4)/(5)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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random231
  • random231
just solve (3x-4)/5=0
jdoe0001
  • jdoe0001
\(\bf f(x)={\color{blue}{ y}}=0\qquad {\color{blue}{ f(x)}}=\cfrac{3x-4}{5}\qquad thus \\ \quad \\ {\color{blue}{ 0}}=\cfrac{3x-4}{5}\impliedby \textit{solve for "x"}\)
jewlzme17
  • jewlzme17
I already know all of that I just don't remember how to solve (3x-4)/5

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freckles
  • freckles
(3x-4)/5 there is nothing to solve here do you mean you don't remember how to solve (3x-4)/5=0?
freckles
  • freckles
the fraction is zero when the top is 0
freckles
  • freckles
that you only have to solve 3x-4=0
jewlzme17
  • jewlzme17
so the zero cancels out the 5?
dinamix
  • dinamix
(3x-4)=0 *5 3x=4 x=
dinamix
  • dinamix
@jewlzme17 u should try little
jewlzme17
  • jewlzme17
I know the answer it 4/3 its just I am having trouble understanding how. You guys are all saying different things and it's confusing. Like can someone just break it down barney style without being rude?
freckles
  • freckles
if 3x-4=0 then 3x has to be 4 another way to say this is 3x=4
freckles
  • freckles
can you solve for x now?
freckles
  • freckles
no one has said anything different
freckles
  • freckles
each of us has given you part of how to get there
freckles
  • freckles
@jdoe0001 showed you exactly what f(x)=0 meant @dinamix showed you how to get to 3x=4
freckles
  • freckles
oh and i forgot to add what I said @freckles said f(x)=0 when the numerator=0
jewlzme17
  • jewlzme17
What I'm confused on is what you do with the denominator?
freckles
  • freckles
the bottom is always 5 it has no deciding factor when the fraction is 0
freckles
  • freckles
do you know that 0/anything is 0 (when anything isn't 0)
freckles
  • freckles
\[h(x)=\frac{f(x)}{g(x)}=0 \text{ when } f(x)=0 \text{ when } x \text{ is in the domain of } h \]
freckles
  • freckles
the only that gets to decide a fraction is 0 when the top is 0 on that function's domain of course
jewlzme17
  • jewlzme17
OKay that makes so much more sense. Thank you
freckles
  • freckles
\[\frac{3x-4}{5}=0 \implies 3x-4=0\]
freckles
  • freckles
though you could have also decide to multiply both sides by 5 and that also works

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