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is that all it says? or is there more that's given?

20 mins , increases , time by 4 that's what i added

so they want you to make up a sequence of your own? or can we use this example?

they wanted me to make up my own based upon what i filled in and the formula above with the a

ok what sequence did you make up on your own?

a(subscript) n=a+d(n-1)

when i fill in the sequence equation it looks like this a(subscript)7=a+4(7-1)

so how would that be written

a = 20 and d = 4
they are plugged into `a+d(n-1)` to get the general nth term

so,
a+d(n-1) = 20+4(n-1) = ???

thank you for you help.

glad to be of help

@jim_thompson5910 need you help again with another 1

go ahead

Use your scenario to write the formula for the 5th term in your sequence using sequence notation.

the equation for geometric sequence is an=a1â€¢rnâˆ’1.

if you said maybe something like "increases by 5%", then it would work

i see what you're saying , I knew something wasn't right. So change it to 5%

then what would i do

the first term is a = 45
the common ratio is r = 0.05 (decimal form of 5%)

no sorry, the common ratio would be 1.05
1+0.05 = 1.05

so it would be a5=45 x1.05(7-1)

change the 5% to 1.05%?

I added on 1 because increasing by 5% is the same as multiplying by 1.05

the nth term should be
\[\Large a(r)^{n-1}\] then you plug in a = 45 and r = 1.05

ok

i have to use that exact equation above \[a _{4=45x 1.05(4}\]

the x= times

the exponent should be n-1 = 4-1
so
\[\LARGE a_4 = 45*(1.05)^{4-1}\]

well no, because i want to find the 5th term. I simplified it so I didn't put the -1 i just did it.

so 5-1

oh, then you want to compute \(\LARGE a_5\) and not \(\LARGE a_4\)

yes it's a5 not a4

they wanted me to find a5 the fifth term.

I see

ok so the answer would be what i said rightttt

yes, it would be \[\LARGE a_5 = 45*(1.05)^{4}\]

Thank you, I may need help in like 3 mins again 1 more

a_(5=45 Ã—ã€–1.05ã€—^(5-1) ) @jim_thompson5910

I think you meant to write
\[\LARGE a_5 = 45 \times 1.05^{5-1}\] right?

Yes, but i don't know how to make it look like that, how do you do that?

the geometric series formula Sn=
a1âˆ’a1rn
1âˆ’r

as for the summation formula, it would be
\[\Large S_n = a*\frac{1-r^n}{1-r}\]

which is equivalent to the form you wrote

where the a is by itself it should be with the 1 at the top

yes the two are equivalent
\[\Large S_n = a*\frac{1-r^n}{1-r} = \frac{a-a*r^n}{1-r}\]

I'm going to screenshot it

yeah which is what I wrote here
\[\Large S_n = \frac{a-a*r^n}{1-r}\]

there are 2 versions of the same thing really

ok

they want you to add up a bunch of terms and use the Sn formula to do it quickly

so for instance, add up the first 8 terms and compute S8

So I"m using what you are saying as a example, because Idon't want to seem as a cheater

you can use another value of n

ok 5

Oh it says use the same scenario

from part 2

so a = 45 and r = 1.05

right ,but i need to make a question now

Maybe I can say Anthony goes to the gym at 10 am for 45mins, then
IDK what im doing

so you have to make a completely different scenario?

no just use the scenario from part 2 to make up a question

but I don't know what numbers are suppose to be in the geometric series
here is the example

is it like the example?

yes

ok than so what would be the geometric series than for the question?

I'm not sure what you're asking exactly?

I think it means 3 numbers that have a common ratio of 5%

you mean they want you to add up the first three terms of the geometric sequence?

idk honestly. I'm just listening to you

does it look like what it mean in the picture

this is a project and it doesn't really explain much

So the question would be "Find the sum of the first 7 terms

yes the work shown above would apply to that question

Thank you, your name should say lifesaver. You just helped me finish out my math class.

I'm glad I could be of help