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anonymous

  • one year ago

okay my questions are #32. (-8-√-2)^2 #33. (2-3i)(3-i)-(4-i)(4+i) then i will have one more but i will have to write it after working these too.

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  1. jim_thompson5910
    • one year ago
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    let's focus on one at a time (one per post to devote the whole post to the question) like before, \[\Large \sqrt{-2} = i\sqrt{2}\] do you agree?

  2. anonymous
    • one year ago
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    yes i agree

  3. jim_thompson5910
    • one year ago
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    |dw:1441069958552:dw|

  4. jim_thompson5910
    • one year ago
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    go ahead and fill out the table (or what you can)

  5. anonymous
    • one year ago
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    |dw:1441069842863:dw|

  6. jim_thompson5910
    • one year ago
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    the root 2 in the lower right corner should be root 4

  7. jim_thompson5910
    • one year ago
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    |dw:1441070341133:dw|

  8. anonymous
    • one year ago
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    then i cross out the -8i√2

  9. jim_thompson5910
    • one year ago
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    why cross that out?

  10. anonymous
    • one year ago
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    i dont know im not sure how this is gonna help me to solve this problem

  11. jim_thompson5910
    • one year ago
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    those terms would go away IF you had +8i*sqrt(2) and -8i*sqrt(2)

  12. jim_thompson5910
    • one year ago
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    but instead we have two copies of -8i*sqrt(2)

  13. jim_thompson5910
    • one year ago
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    \[\large i^2*\sqrt{4} = -1*2 = -2\]

  14. jim_thompson5910
    • one year ago
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    |dw:1441070689367:dw|

  15. anonymous
    • one year ago
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    okay

  16. jim_thompson5910
    • one year ago
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    now add up all the terms inside the boxes \[\Large 64 + (-8i\sqrt{2})+(-8i\sqrt{2})+(-2) = 62 - 16i\sqrt{2}\]

  17. jim_thompson5910
    • one year ago
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    make sense?

  18. anonymous
    • one year ago
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    how do you get rid of the sqrt on the two or does it need to stay.

  19. jim_thompson5910
    • one year ago
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    there's nothing we can do to simplify further, so we leave as is

  20. anonymous
    • one year ago
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    so this is the answer?

  21. jim_thompson5910
    • one year ago
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    yes, \[\Large \left(-8-\sqrt{-2}\right)^2 = 62 - 16i\sqrt{2}\]

  22. anonymous
    • one year ago
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    actually i will have one more additional problem but i will post each into a new window. thank you thoughtfor the help bc that was the correct problem.

  23. jim_thompson5910
    • one year ago
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    yeah one per post is a good idea to avoid clutter

  24. jim_thompson5910
    • one year ago
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    and avoid lag too

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