anonymous
  • anonymous
PLEASE HELP! Simplify the rational expressions. State any excluded values. Screenshot included! Medal!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
jim_thompson5910
  • jim_thompson5910
|dw:1441070374438:dw|
jim_thompson5910
  • jim_thompson5910
the numerator 3x-6 can be factored 3 and 6 have the factor 3 in common, so we can factor out this common factor 3x-6 = 3(x-2) notice if you were to distribute the 3 back in, you'd get 3x-6

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jim_thompson5910
  • jim_thompson5910
|dw:1441070429569:dw| at this point, I'm sure you see what to do next
anonymous
  • anonymous
To be quite honest I've never done this math before
anonymous
  • anonymous
cancel out the x's or something? I have no clue
jim_thompson5910
  • jim_thompson5910
the `x-2` terms will divide to 1 recall that x/x = 1 in english: "any term, except 0, divided by itself will give you 1"
jim_thompson5910
  • jim_thompson5910
|dw:1441070578033:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1441070595126:dw|
anonymous
  • anonymous
okay I think I get it would you help me with the second one?
jim_thompson5910
  • jim_thompson5910
|dw:1441070758108:dw|
jim_thompson5910
  • jim_thompson5910
are you able to factor \[\Large x^2+3x-10\] at all?
jim_thompson5910
  • jim_thompson5910
oh and I nearly forgot: for #8, the excluded value is x = 2. This value must be excluded to avoid dividing by zero
anonymous
  • anonymous
wait what?
anonymous
  • anonymous
so the answer is x = 2
jim_thompson5910
  • jim_thompson5910
no I'm saying that x = 2 is kicked out because if x = 2, then the denominator x-2 turns to 0 (we can't divide by zero). This is all for #8
jim_thompson5910
  • jim_thompson5910
\[\Large \frac{3x-6}{x-2}\] simplifies to 3 (as shown above in the drawings). The restriction is that \(\large x\ne 2\)
jim_thompson5910
  • jim_thompson5910
make sense?
anonymous
  • anonymous
yes!
jim_thompson5910
  • jim_thompson5910
ok onto #9
jim_thompson5910
  • jim_thompson5910
|dw:1441071205777:dw|
anonymous
  • anonymous
no like I don't get how to do it?
jim_thompson5910
  • jim_thompson5910
think of 2 numbers that multiply to -10 AND add to +3
anonymous
  • anonymous
if you showed me how to do it step by step 1.) 2.) 3.) I would know how to do it
anonymous
  • anonymous
-2 * 5?
jim_thompson5910
  • jim_thompson5910
yes, -2*5 = -10 -2+5 = 3
jim_thompson5910
  • jim_thompson5910
since the two numbers are -2 and 5, this means x^2+3x-10 factors to (x-2)(x+5)
anonymous
  • anonymous
so x-2/-2*5=3?
jim_thompson5910
  • jim_thompson5910
|dw:1441071380260:dw|
jim_thompson5910
  • jim_thompson5910
like in #8, the `x-2` terms divide to 1 and cancel out effectively |dw:1441071502600:dw|
anonymous
  • anonymous
oh
jim_thompson5910
  • jim_thompson5910
|dw:1441071578172:dw|
jim_thompson5910
  • jim_thompson5910
so hopefully you see how \[\Large \frac{x-2}{x^2+3x-10} = \frac{1}{x+5}\] the restrictions are that \(\large x \ne 2\) or \(\large x \ne -5\) to avoid division by zero errors
anonymous
  • anonymous
I get it a little now it will just take me more practice
jim_thompson5910
  • jim_thompson5910
here's a page that offers more practice http://www.purplemath.com/modules/rtnldefs2.htm

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