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i am dizzy already

how many squares
how many parallelograms

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none of the above

38

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im not sure if that is possible because then the 6 are vertical

that why in the beginning they were like oh its horizontal given this picture as it is

dan's
\(\large \dbinom{2}{1}*(4+\dbinom{6}{2})\) looks neat to me!

With horizontal only, I also have
\(\Large 2*\dbinom{6}{6}*(\dbinom{6}{2}+4\dbinom{2}{2})=38\)

did i do something wrong?

haha xD

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i tried 2*(3choose 2 * 7 choose 2) - (3 choose 2)^2

29 squares
easy to count one by one :)

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thanks @ganeshie8 :D

right thats what i was thinking

right im just translating ur math symbols to layman english

o boy

like the number of every unique rectangle?

here the group is the set of all symmetries of given pattern
operation is "composition"

i didn't understand this
\(\large \dbinom{2}{1}\times \left(4+\dbinom{6}{2}\right)\)

teamviewer ?

wait

sry no teamviewer , m on mobile connection

2 rows

look at the given pattern
how many rows have at least 6 squares ?

2 rows ?

ok

let me know once you digest step1

i digested

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after step1, situation might look something like above

lets see step2

yes

2*6C2+4*2C2

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