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\[(2-3i)(3-i)-(4-i)(4+i)\]

(2-3i)(3-i)-(4-i)(4+i)

theres supposed to be one more parenthases after 3i

am i foiling this or is that not the right way to go about this problem?

you can FOIL or use the table like last time. Which option works best for you?

foil the table is a little confusing.

ok what do you get when you FOIL (2-3i)(3-i)

3-11i

correct

how about `(4-i)(4+i)` ?

that is 15

brb

not 15, but you are close

try again

okay

where did i go wrong with my problem i will show you my work.

(4-i)(4+i)
(a-b)(a+b) =a^2-b^2
4^2 -i^2
16-(-1)=17

could the answer be 187i+51?

|dw:1441072256502:dw|

i^2 is -1
so \(\Large 16-\color{red}{i^2}\) turns into \(\Large 16-\color{red}{(-1)}\)

Do you see what I mean @huntergirl1 ?

yes now i do @jim_thompson5910

@sayomi you were correct and yes @jim_thompson5910 i do understand

I'm glad it's making sense

so the ending result is 51-187i

okay do you wnt me to start a new window for the next problem? or to place it here?

how are you getting `51-187i` ?

I wrote the answer above

bc you put 17 back into the problem

are you saying that they wanted you to multiply `(2-3i)(3-i)` and `(4-i)(4+i)` ??

actually i put those answers both into the website they were both incorrect

hwy was the answer supposed to be -14-11i?

why

because the 3 and -17 combine to -14

(3-11i) - (17) = 3-11i - 17 = (3-17) + (-11i) = -14 - 11i

oh okay.

will you be on to check a few more problems before I submit them?

sure

thank you!!!!!!!!!!!!

no problem

okay i have one to check its similar to the last problem

|dw:1441074082197:dw|

what did i do wrong?

you didn't foil correctly

okay i guess the sqrt part mixed me up

i also tried the box method too

|dw:1441074547608:dw|

agreed so far?

okay thats how i started it on my paper too

ok go ahead and fill it out

|dw:1441074610390:dw|

right?

same with the -i and -i being multiplied in the lower right box
|dw:1441074956036:dw|

so instead of a negative is a possitive

okay

so is the answer 18 instead?

no :( dang it please help me i have until 11:50 to submit these

now add up the terms inside the boxes
\[\Large 16 + 4i\sqrt{2} + 4i\sqrt{2}+(-2) = 14+8i\sqrt{2}\]

|dw:1441075415932:dw|

okay that makes since

|dw:1441075435745:dw|

okay no do i leave it as 14-8i√2

+8i not -8i

\[\Large 14 + 8i\sqrt{2}\] is as simplified as it gets

bc the sqrt of 2 cant be any other number? oh okay so possitive 8i

okay thats what i thought

you're welcome, glad to be of help