okay help with this problem and then one more and I wont need anymore help tonight. (2-3i(3-i)-(4-i)(4+i)

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okay help with this problem and then one more and I wont need anymore help tonight. (2-3i(3-i)-(4-i)(4+i)

Algebra
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\[(2-3i)(3-i)-(4-i)(4+i)\]
(2-3i)(3-i)-(4-i)(4+i)
theres supposed to be one more parenthases after 3i

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am i foiling this or is that not the right way to go about this problem?
you can FOIL or use the table like last time. Which option works best for you?
foil the table is a little confusing.
ok what do you get when you FOIL (2-3i)(3-i)
(2 -3i)(3-i)-(4-i)(4+i) (2)(3-i)-(3i)(3-i)-(4^2-i^2) Multiply find the value Note i^2 = -1 Source: mathskey.com
3-11i
correct
how about `(4-i)(4+i)` ?
that is 15
brb
not 15, but you are close
try again
okay
where did i go wrong with my problem i will show you my work.
(4-i)(4+i) (a-b)(a+b) =a^2-b^2 4^2 -i^2 16-(-1)=17
could the answer be 187i+51?
|dw:1441072256502:dw|
i^2 is -1 so \(\Large 16-\color{red}{i^2}\) turns into \(\Large 16-\color{red}{(-1)}\)
im not sure @sayomi
Do you see what I mean @huntergirl1 ?
yes now i do @jim_thompson5910
ok great, so 16-(-1) = 16+1 = 17 --------------------- \[\large \color{red}{(2-3i)(3-i)}-\color{blue}{(4-i)(4+i)} =\color{red}{3-11i}-\color{blue}{17} = -14-11i\]
@sayomi you were correct and yes @jim_thompson5910 i do understand
I'm glad it's making sense
so the ending result is 51-187i
okay do you wnt me to start a new window for the next problem? or to place it here?
how are you getting `51-187i` ?
I wrote the answer above
bc you put 17 back into the problem
are you saying that they wanted you to multiply `(2-3i)(3-i)` and `(4-i)(4+i)` ??
actually i put those answers both into the website they were both incorrect
hwy was the answer supposed to be -14-11i?
why
because the 3 and -17 combine to -14
(3-11i) - (17) = 3-11i - 17 = (3-17) + (-11i) = -14 - 11i
oh okay.
will you be on to check a few more problems before I submit them?
sure
thank you!!!!!!!!!!!!
no problem
okay i have one to check its similar to the last problem
|dw:1441074082197:dw|
what did i do wrong?
you didn't foil correctly
okay i guess the sqrt part mixed me up
i also tried the box method too
|dw:1441074547608:dw|
what we do is make a 2x2 box 2 rows and 2 columns the terms of each factor will go along the outside like this |dw:1441074595637:dw|
agreed so far?
okay thats how i started it on my paper too
ok go ahead and fill it out
|dw:1441074610390:dw|
-4 times \(\large -i\sqrt{2}\) should be \(\large +4i\sqrt{2}\) the two negatives cancel |dw:1441074917203:dw|
right?
same with the -i and -i being multiplied in the lower right box |dw:1441074956036:dw|
so instead of a negative is a possitive
so after filling the boxes and simplifying the expressions in each box, we end up with |dw:1441075014939:dw| since \[\Large i^2*\sqrt{4} = -1*2 = -2\]
okay
so is the answer 18 instead?
no :( dang it please help me i have until 11:50 to submit these
now add up the terms inside the boxes \[\Large 16 + 4i\sqrt{2} + 4i\sqrt{2}+(-2) = 14+8i\sqrt{2}\]
|dw:1441075415932:dw|
okay that makes since
|dw:1441075435745:dw|
okay no do i leave it as 14-8i√2
+8i not -8i
\[\Large 14 + 8i\sqrt{2}\] is as simplified as it gets
bc the sqrt of 2 cant be any other number? oh okay so possitive 8i
okay thats what i thought
okay so im just going to bed im to tired to work on these i have to be up @ 5 thank you for your help (:
you're welcome, glad to be of help

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