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anonymous

  • one year ago

A truck is worth $80000 when purchased. It is depreciated linearly over 7 years ad has a scrap value of $6000.00. A linear equation expressing the trucks book value at the end of t years is. I got v(t)= -74000/7(t) + 80000. Is that correct?

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  1. anonymous
    • one year ago
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    find the equation of the line through \((0,80000)\) and \((7,60000)\) if i am reading it correctly b

  2. anonymous
    • one year ago
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    b?

  3. anonymous
    • one year ago
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    is there a choice that says \[y=-\frac{2000}{7}x+80000\]?

  4. anonymous
    • one year ago
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    \[no, there is -52000/7t + 6000, -74000/7t+6000, 68000/7t-6000, -52000/7t+80000 and mine alongwith F none\]

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