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Still trying to get through these review questions from what I missed while ill.
Yep, those are the correct systems. I should have made sure to mention that they were row labels and not exponents. I'm sorry if that was confusing.
i got it
if you pick some random \(h\) and \(k\) there will probably be one unique solution
if you multiply the first equation by 2 you get \[2x_1-6x_2=2\\ 2x_2+hx_2=k\]
if you make \(h=-6\) and \(k=2\) they will be the same line exactly so there will be infinitely many solutions
if you make \(h=-6\) and \(k=\) anything but 2, they will be parallel lines with no intersection
Oh wow! How did you figure that out?
i am the satellite
ok in truth if you wanted to solve it you would have to match up the coefficients to use "elimination" i just matched up the coefficients of the \(x_1\) term by doubling the first one
Hehehe, that makes sense.