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anonymous
 one year ago
1. For the following scores, find the mean, median, and the mode. Which would be the most appropriate measure for this data set?
2, 2, 0, 5,1, 4,1, 3, 0, 0, 1, 4, 4, 0,1, 4, 3, 4, 2, 1
anonymous
 one year ago
1. For the following scores, find the mean, median, and the mode. Which would be the most appropriate measure for this data set? 2, 2, 0, 5,1, 4,1, 3, 0, 0, 1, 4, 4, 0,1, 4, 3, 4, 2, 1

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madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2first arrange the data in ascending order

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2@jessicajanece come on do it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to find mean, add all the numbers then divide by the number of numbers there are in this case 19

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.20,0,0,0,1,1,1,1,1,2,2,2,3,3,4,4,4,4,4,5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the mode is the number that is the most frequent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and the median you just cross off number from both sides until you hit the middle

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2mean =42/20=2.1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know how to find the mean median and mode, just confused on what would be the most appropriate measure for this set of data?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not really sure what the "appropriate measure" means

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2for ungrouped data the best measure is always the mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much! That makes much more sense now..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0^ there you have it!! sorry i couldn't help better

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I appreciate both of your help!!!

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2but you helped a lot:)@hl147

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2your welcome:)
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