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anonymous
 one year ago
Solve the system.
x1  5x2 + 4x3 = 3
2x1  7x2 + 3x3 = 2
2x1 + x2 + 7x3 = 1
anonymous
 one year ago
Solve the system. x1  5x2 + 4x3 = 3 2x1  7x2 + 3x3 = 2 2x1 + x2 + 7x3 = 1

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that we are to end up with a matrices in the form of 1 ? ? ? 0 1 ? ? 0 0 1 ?

Hero
 one year ago
Best ResponseYou've already chosen the best response.3@LadyInkblot have you converted the system to a matrix yet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. It starts out as a matrix of 1 5 4 3 2 7 3 2 2 1 7 1

Hero
 one year ago
Best ResponseYou've already chosen the best response.3How far have you gotten with reducing the matrix?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know if this is correct, but so far I have 1 5 4 3 0 3 5 4 0 10 15 7

Hero
 one year ago
Best ResponseYou've already chosen the best response.3Looks like you attempted to perform a couple of row operations. Do you remember which row operations you performed?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I preformed (I believe) 2R1 + R3 and 2R1  R2

Hero
 one year ago
Best ResponseYou've already chosen the best response.3I can double check that for you. In the mean time, do you know how you plan to continue reducing the matrix from here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I do not know how to proceed, which is why I came here for help ^_^;

Hero
 one year ago
Best ResponseYou've already chosen the best response.3May I suggest a different approach?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that I need to get rid of the 10x2, but I'm not sure how to go about it, since I don't want anything to go back into my third row first column spot.

Hero
 one year ago
Best ResponseYou've already chosen the best response.3What if, starting with the original matrix, you performed the following operations to start with: R2 + R3, then 2R1 + R2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just row 2 + row 3? not multiplying anything?

Hero
 one year ago
Best ResponseYou've already chosen the best response.3Yes, actually do R2 + R3, then 2R1 + R2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay. I'll get back to you in a minute then with my answer...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so I got 1 5 4 3 0 3 5 0 0 6 4 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But then I'll still have to get rid of the 6 in the third row... so what about 2R2 + r3?

Hero
 one year ago
Best ResponseYou've already chosen the best response.3You should double check your work for those 2 operations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, what's wrong with it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I tried again and got something different 1 5 4 3 0 3 5 8 0 6 10 3

Hero
 one year ago
Best ResponseYou've already chosen the best response.3The 1st and 3rd row are correct. The second row has a mistake with the 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah. Would it be a 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 5 4 3 0 3 5 4 0 0 0 5

Hero
 one year ago
Best ResponseYou've already chosen the best response.3You're jumping too far ahead.

Hero
 one year ago
Best ResponseYou've already chosen the best response.3Please post just the first two operations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 5 4 3 0 3 5 4 0 6 10 3

Hero
 one year ago
Best ResponseYou've already chosen the best response.3Okay, yes, and in the next step, you figure out that you have a row of the form 0 0 0 b which is an invalid row.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. What does that mean, an invalid row. 1 5 4 3 0 3 5 4 0 0 0 5

Hero
 one year ago
Best ResponseYou've already chosen the best response.3If you converted the last row back to an algebraic equation, you'd have the form 0x + 0y + 0z = 5 or just 0 = 5, but 0 = 5 is a false statement.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. So what does that mean for the answer to the problem then. Just that the solution is invalid?

Hero
 one year ago
Best ResponseYou've already chosen the best response.3It means the system cannot be solved and therefore has no solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, that makes sense. Thank you!

Hero
 one year ago
Best ResponseYou've already chosen the best response.3You're welcome. Great work on your problem.
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