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anonymous

  • one year ago

In the figure below, the polygons are similar. Find the value of x and y.

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  1. anonymous
    • one year ago
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  2. LynFran
    • one year ago
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    just by looking at this i can say y=3 and x=4 ...lol

  3. anonymous
    • one year ago
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    are you sure? how did you get that?

  4. LynFran
    • one year ago
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    |dw:1441087292025:dw|

  5. LynFran
    • one year ago
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    using the Pythagorean c^2=a^2+b^2 let a=6 and b=8 therefore c= sq.rt 36+64 = sq.rt 100 =10

  6. LynFran
    • one year ago
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    now looking at |dw:1441087660879:dw|

  7. LynFran
    • one year ago
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    we see that the c which =10 being divided by 2 ...to give our new triangle for our new c ... 10/2 =5

  8. LynFran
    • one year ago
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    so we can divide our a by 2 to give 3 and also divide our b by 2 to give 4 so x=4 and y=3 if we use Pythagorean a^2+b^2=c^2 sq.rt 9+16=c sq.rt 25=c 5=c

  9. LynFran
    • one year ago
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    ok here a much easier way to do this.. in term of ratio \[\frac{ y }{ 6 }=\frac{ x }{ 8 }=\frac{ 5 }{ 10 }\]so\[\frac{ y }{ 6 }=\frac{ 5 }{ 10 }\]\[\frac{ y }{ 6 }=\frac{ 1 }{ 2 }\]\[y=\frac{ 1 }{ 2 }*6\]\[y=3\]and \[\frac{ x }{ 8 }=\frac{ 5 }{ 10 }\]\[x=\frac{ 1 }{ 2 }*8\]\[x=4\] @pleasehelpme5

  10. anonymous
    • one year ago
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    omg thank you so much can you help me with another problem

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