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anonymous

  • one year ago

Solve the system using any method. 5x-5y=0 7x-8y=8

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  1. freckles
    • one year ago
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    notice the first equation can be written as 5x=5y or x=y just sub this into the second equation

  2. anonymous
    • one year ago
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    |dw:1441080456430:dw| Is this how you set it up?

  3. Abhisar
    • one year ago
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    Solve the system using any method. 5x-5y=0 7x-8y=8 You can write the first equation as \(8y-8x=0\) Add this to the second equation and you will an equation in terms of x only. Find the value of x and then substitute it in any one of the parent equation to get value of y

  4. anonymous
    • one year ago
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    why would the 1st equation into 8y=8x=0?

  5. Abhisar
    • one year ago
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    \(5x-5y=0 \\ \Rightarrow 5(x-y)=0 \\ \Rightarrow 8x-8y=0 \Rightarrow 8y-8x=0\)

  6. Abhisar
    • one year ago
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    Right? Now the second equation has -8y, so we can cancel them out out and life will become happy c:

  7. midhun.madhu1987
    • one year ago
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    |dw:1441080926309:dw|

  8. Abhisar
    • one year ago
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    Yes, you can do that way too

  9. anonymous
    • one year ago
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    Oh i understand now. :D Thanks so much!

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