YumYum247
  • YumYum247
Help me please!!! :D
Physics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[H=\frac{u^2\sin^2(\theta)}{2g}\]
YumYum247
  • YumYum247
|dw:1441080373399:dw|
anonymous
  • anonymous
Use the formula I wrote

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YumYum247
  • YumYum247
but i din't know what u^2 means tho??????
YumYum247
  • YumYum247
initial velocity?
anonymous
  • anonymous
yep
YumYum247
  • YumYum247
aight.....Thanks!!!
YumYum247
  • YumYum247
but that formula is used to find the maximum horizontal displacement tho!! i need the vertical displacement.
YumYum247
  • YumYum247
@welshfella please help me!!! :)
anonymous
  • anonymous
That gives the maximum vertical displacement, the H stands for height, the formula is correct
anonymous
  • anonymous
For horizontal displacement we have, \[R=ucos(\theta)T=ucos(\theta).(\frac{2usin(\theta)}{g})=\frac{u^2.(2\sin(\theta)\cos(\theta))}{g}=\frac{u^2\sin(2\theta)}{g}\]
YumYum247
  • YumYum247
sorry i didn't see the 2g at the bottom....hehehehehhehe :"D Thanks Luv!!

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