## anonymous one year ago If f and g are differentiable function such that f(2)=3, f'(2)=-1, f'(3)=7, g(2)=-5, and g'(2)=2, find (g-f)'(2). I don't need to know this exact answer - if some could just tell me where to find the rules for this kind of math, that'd be great, thanks.

1. freckles

$(g-f)'(x)=g'(x)-f'(x) \text{ by difference rule }$

2. freckles
3. anonymous

There we go. THERE we go. I was so confused when a later part used (fg)'(2) and it wasn't just (f)'(2) x (g)'(2). Thanks.

4. freckles

np yeah (fg)' needs product rule :)