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DF001

  • one year ago

Help Simplifying and write answer with positive exponents only. (-2x^6y^-5/3x^-2y^4)^-3

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  1. DF001
    • one year ago
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    |dw:1441083048569:dw|

  2. DF001
    • one year ago
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    \[\left(\begin{matrix}\ \frac{ -2x^6y^-5 }{ 3x^-2y^4 }\ \end{matrix}\right) ^3\]

  3. DF001
    • one year ago
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    My calculations are: 27y^27 / -8x^24

  4. midhun.madhu1987
    • one year ago
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    |dw:1441083217764:dw|

  5. midhun.madhu1987
    • one year ago
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    Now apply the formula: |dw:1441083359642:dw|

  6. DF001
    • one year ago
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    my answer is \[\frac{ 27y ^{27} }{ -8x^{24} }\]

  7. DF001
    • one year ago
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    I subtracted the exponents and then I flipped the fraction to change the outside exponent into a positive 3

  8. midhun.madhu1987
    • one year ago
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    |dw:1441083494401:dw|

  9. DF001
    • one year ago
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    can that be written as the way i wrote it?

  10. midhun.madhu1987
    • one year ago
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    |dw:1441083579991:dw|

  11. DF001
    • one year ago
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    -3

  12. midhun.madhu1987
    • one year ago
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    I did with +3.. let me do the other way too

  13. DF001
    • one year ago
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    How I did it is, I subtracted big exponent to small and then I flipped the fraction due to the 3 being negative.

  14. midhun.madhu1987
    • one year ago
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    yes thats correct....

  15. DF001
    • one year ago
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    thank you.

  16. DF001
    • one year ago
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    but i thought it was weird for a negative to be the denominator

  17. midhun.madhu1987
    • one year ago
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    |dw:1441083656194:dw|

  18. midhun.madhu1987
    • one year ago
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    |dw:1441083716187:dw|

  19. DF001
    • one year ago
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    Yes, i did it like that and then I subtracted the bigger exponents to the smaller

  20. midhun.madhu1987
    • one year ago
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    So the answer will be: |dw:1441083787155:dw|

  21. DF001
    • one year ago
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    thank you.

  22. midhun.madhu1987
    • one year ago
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    yw :)

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