## anonymous one year ago counting question

1. anonymous

a volley ball league with 4 teams ,each team plays exactly 4 times with each of the other 3 teams in the league .what is the total number of games played in this league? a)4 b)6 c)12 d)16 e)24

2. anonymous

@imqwerty

3. anonymous

handshake problem times 4

4. anonymous

what of meaning of handshake

5. anonymous

|dw:1441084213468:dw|

6. anonymous

7. anonymous

ok thank u

8. anonymous

@pgpilot326

9. anonymous

10. anonymous

ok can i solve it by npr or ncr@pgpilot326

11. anonymous

combinations are not needed... nor useful in this problem

12. anonymous

yes right,it can be very easily solve by combinations

13. anonymous

ncr

14. anonymous

yes,now try to solve it

15. anonymous

how many games are there if each team plays the other teams exactly once?

16. anonymous

hassan, you are leading nourage down the wrong path!

17. anonymous

ncr is combinations right

18. anonymous

@pgpilot326 try to solve it by combinations i think that really works

19. anonymous

but first let him solve it,then if he couldn't i will show you

20. anonymous

combinations is not the way

21. anonymous

ncr is combinations or not

22. anonymous

@Nourage and don't forget to multiply the answer with how much these teams gonna play with each other

23. anonymous

@Nourage do you know the formula of combinations

24. anonymous

please explain why you think combinations is relevant here...

25. anonymous

no i don t know hassan

26. anonymous

$nCr=\frac{ n! }{ n!(n-r)! }$

27. anonymous

plz hlp

28. anonymous

you know what is n and r?

29. anonymous

30. anonymous

or not

31. anonymous

did you look up the "handshake problem?" and did you see my drawing?

32. anonymous

combinations is ncr in the calc

33. anonymous

right or wrong

34. anonymous

hassan

35. anonymous

nope friend, n is the total number of teams and r is the team which will play just like two people will involve in a handshake two teams will participate to play a match,that's why we take r=2

36. anonymous

again, @Hassan3130 explain your reasoning for combinations! it's wrong and you're confusing the issue!

37. anonymous

i can t understand

38. anonymous

plz help

39. anonymous

$\frac{ 4! }{ 2!2! }=\frac{ 24 }{4 }$

40. anonymous

and wt is c

41. anonymous

i am saying to try for combination because i think it's easy to find but if you don't read much about this topic than you can follow what @pgpilot326 said

42. anonymous

ok but can u said to me how to solve it by ncr or npr in the calc

43. anonymous

@Hassan3130

44. anonymous

yes you can solve it from scientific caluclator

45. anonymous

how plz

46. anonymous

@Hassan3130

47. anonymous

but firstly you have to know the value of r and n

48. anonymous

r is 2 and n is4

49. anonymous

right

50. anonymous

yes

51. anonymous

then what i can i do on calc

52. anonymous

have you find it written on calculator"nCr"

53. anonymous

4n2

54. anonymous

4c2

55. anonymous

6

56. anonymous

yes right

57. anonymous

then 6*4 right

58. anonymous

yes absolutely right

59. anonymous

cause they will play with each other 4 times

60. anonymous

thank u @Hassan3130 and @pgpilot326

61. anonymous

62. anonymous

well done now i hope that you can solve questions like this

63. anonymous

sure hassan

64. anonymous

look at my 2nd response... see if that makes more sense. combination is valid

65. anonymous

thank u @pgpilot326

66. anonymous

i m a fan of u @Hassan3130 and pgpilot326

67. anonymous

bi hassan