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handshake problem times 4

what of meaning of handshake

|dw:1441084213468:dw|

google "handshake problem"

ok thank u

do you know about "combinations"??

ok can i solve it by npr or ncr@pgpilot326

combinations are not needed... nor useful in this problem

yes right,it can be very easily solve by combinations

ncr

yes,now try to solve it

how many games are there if each team plays the other teams exactly once?

hassan, you are leading nourage down the wrong path!

ncr is combinations right

@pgpilot326 try to solve it by combinations i think that really works

but first let him solve it,then if he couldn't i will show you

combinations is not the way

ncr is combinations or not

please explain why you think combinations is relevant here...

no i don t know hassan

\[nCr=\frac{ n! }{ n!(n-r)! }\]

plz hlp

you know what is n and r?

r radius

or not

did you look up the "handshake problem?" and did you see my drawing?

combinations is ncr in the calc

right or wrong

hassan

i can t understand

plz help

\[\frac{ 4! }{ 2!2! }=\frac{ 24 }{4 }\]

and wt is c

ok but can u said to me how to solve it by ncr or npr in the calc

yes you can solve it from scientific caluclator

how plz

but firstly you have to know the value of r and n

r is 2 and n is4

right

yes

then what i can i do on calc

have you find it written on calculator"nCr"

4n2

4c2

yes right

then 6*4 right

yes absolutely right

cause they will play with each other 4 times

thank u @Hassan3130 and @pgpilot326

your the best

well done now i hope that you can solve questions like this

sure hassan

look at my 2nd response... see if that makes more sense. combination is valid

thank u @pgpilot326

i m a fan of u @Hassan3130 and pgpilot326

bi hassan