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anonymous
 one year ago
counting question
anonymous
 one year ago
counting question

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a volley ball league with 4 teams ,each team plays exactly 4 times with each of the other 3 teams in the league .what is the total number of games played in this league? a)4 b)6 c)12 d)16 e)24

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0handshake problem times 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what of meaning of handshake

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441084213468:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0google "handshake problem"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know about "combinations"??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok can i solve it by npr or ncr@pgpilot326

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0combinations are not needed... nor useful in this problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes right,it can be very easily solve by combinations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes,now try to solve it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how many games are there if each team plays the other teams exactly once?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hassan, you are leading nourage down the wrong path!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ncr is combinations right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@pgpilot326 try to solve it by combinations i think that really works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but first let him solve it,then if he couldn't i will show you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0combinations is not the way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ncr is combinations or not

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nourage and don't forget to multiply the answer with how much these teams gonna play with each other

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nourage do you know the formula of combinations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please explain why you think combinations is relevant here...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i don t know hassan

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[nCr=\frac{ n! }{ n!(nr)! }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know what is n and r?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did you look up the "handshake problem?" and did you see my drawing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0combinations is ncr in the calc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nope friend, n is the total number of teams and r is the team which will play just like two people will involve in a handshake two teams will participate to play a match,that's why we take r=2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0again, @Hassan3130 explain your reasoning for combinations! it's wrong and you're confusing the issue!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4! }{ 2!2! }=\frac{ 24 }{4 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am saying to try for combination because i think it's easy to find but if you don't read much about this topic than you can follow what @pgpilot326 said

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok but can u said to me how to solve it by ncr or npr in the calc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes you can solve it from scientific caluclator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but firstly you have to know the value of r and n

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then what i can i do on calc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0have you find it written on calculator"nCr"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes absolutely right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cause they will play with each other 4 times

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank u @Hassan3130 and @pgpilot326

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well done now i hope that you can solve questions like this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0look at my 2nd response... see if that makes more sense. combination is valid

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i m a fan of u @Hassan3130 and pgpilot326
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