anonymous
  • anonymous
counting question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
a volley ball league with 4 teams ,each team plays exactly 4 times with each of the other 3 teams in the league .what is the total number of games played in this league? a)4 b)6 c)12 d)16 e)24
anonymous
  • anonymous
@imqwerty
anonymous
  • anonymous
handshake problem times 4

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More answers

anonymous
  • anonymous
what of meaning of handshake
anonymous
  • anonymous
|dw:1441084213468:dw|
anonymous
  • anonymous
google "handshake problem"
anonymous
  • anonymous
ok thank u
anonymous
  • anonymous
@pgpilot326
anonymous
  • anonymous
do you know about "combinations"??
anonymous
  • anonymous
ok can i solve it by npr or ncr@pgpilot326
anonymous
  • anonymous
combinations are not needed... nor useful in this problem
anonymous
  • anonymous
yes right,it can be very easily solve by combinations
anonymous
  • anonymous
ncr
anonymous
  • anonymous
yes,now try to solve it
anonymous
  • anonymous
how many games are there if each team plays the other teams exactly once?
anonymous
  • anonymous
hassan, you are leading nourage down the wrong path!
anonymous
  • anonymous
ncr is combinations right
anonymous
  • anonymous
@pgpilot326 try to solve it by combinations i think that really works
anonymous
  • anonymous
but first let him solve it,then if he couldn't i will show you
anonymous
  • anonymous
combinations is not the way
anonymous
  • anonymous
ncr is combinations or not
anonymous
  • anonymous
@Nourage and don't forget to multiply the answer with how much these teams gonna play with each other
anonymous
  • anonymous
@Nourage do you know the formula of combinations
anonymous
  • anonymous
please explain why you think combinations is relevant here...
anonymous
  • anonymous
no i don t know hassan
anonymous
  • anonymous
\[nCr=\frac{ n! }{ n!(n-r)! }\]
anonymous
  • anonymous
plz hlp
anonymous
  • anonymous
you know what is n and r?
anonymous
  • anonymous
r radius
anonymous
  • anonymous
or not
anonymous
  • anonymous
did you look up the "handshake problem?" and did you see my drawing?
anonymous
  • anonymous
combinations is ncr in the calc
anonymous
  • anonymous
right or wrong
anonymous
  • anonymous
hassan
anonymous
  • anonymous
nope friend, n is the total number of teams and r is the team which will play just like two people will involve in a handshake two teams will participate to play a match,that's why we take r=2
anonymous
  • anonymous
again, @Hassan3130 explain your reasoning for combinations! it's wrong and you're confusing the issue!
anonymous
  • anonymous
i can t understand
anonymous
  • anonymous
plz help
anonymous
  • anonymous
\[\frac{ 4! }{ 2!2! }=\frac{ 24 }{4 }\]
anonymous
  • anonymous
and wt is c
anonymous
  • anonymous
i am saying to try for combination because i think it's easy to find but if you don't read much about this topic than you can follow what @pgpilot326 said
anonymous
  • anonymous
ok but can u said to me how to solve it by ncr or npr in the calc
anonymous
  • anonymous
@Hassan3130
anonymous
  • anonymous
yes you can solve it from scientific caluclator
anonymous
  • anonymous
how plz
anonymous
  • anonymous
@Hassan3130
anonymous
  • anonymous
but firstly you have to know the value of r and n
anonymous
  • anonymous
r is 2 and n is4
anonymous
  • anonymous
right
anonymous
  • anonymous
yes
anonymous
  • anonymous
then what i can i do on calc
anonymous
  • anonymous
have you find it written on calculator"nCr"
anonymous
  • anonymous
4n2
anonymous
  • anonymous
4c2
anonymous
  • anonymous
6
anonymous
  • anonymous
yes right
anonymous
  • anonymous
then 6*4 right
anonymous
  • anonymous
yes absolutely right
anonymous
  • anonymous
cause they will play with each other 4 times
anonymous
  • anonymous
thank u @Hassan3130 and @pgpilot326
anonymous
  • anonymous
your the best
anonymous
  • anonymous
well done now i hope that you can solve questions like this
anonymous
  • anonymous
sure hassan
anonymous
  • anonymous
look at my 2nd response... see if that makes more sense. combination is valid
anonymous
  • anonymous
thank u @pgpilot326
anonymous
  • anonymous
i m a fan of u @Hassan3130 and pgpilot326
anonymous
  • anonymous
bi hassan

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