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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    a volley ball league with 4 teams ,each team plays exactly 4 times with each of the other 3 teams in the league .what is the total number of games played in this league? a)4 b)6 c)12 d)16 e)24

  2. anonymous
    • one year ago
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    @imqwerty

  3. anonymous
    • one year ago
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    handshake problem times 4

  4. anonymous
    • one year ago
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    what of meaning of handshake

  5. anonymous
    • one year ago
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    |dw:1441084213468:dw|

  6. anonymous
    • one year ago
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    google "handshake problem"

  7. anonymous
    • one year ago
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    ok thank u

  8. anonymous
    • one year ago
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    @pgpilot326

  9. anonymous
    • one year ago
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    do you know about "combinations"??

  10. anonymous
    • one year ago
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    ok can i solve it by npr or ncr@pgpilot326

  11. anonymous
    • one year ago
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    combinations are not needed... nor useful in this problem

  12. anonymous
    • one year ago
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    yes right,it can be very easily solve by combinations

  13. anonymous
    • one year ago
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    ncr

  14. anonymous
    • one year ago
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    yes,now try to solve it

  15. anonymous
    • one year ago
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    how many games are there if each team plays the other teams exactly once?

  16. anonymous
    • one year ago
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    hassan, you are leading nourage down the wrong path!

  17. anonymous
    • one year ago
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    ncr is combinations right

  18. anonymous
    • one year ago
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    @pgpilot326 try to solve it by combinations i think that really works

  19. anonymous
    • one year ago
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    but first let him solve it,then if he couldn't i will show you

  20. anonymous
    • one year ago
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    combinations is not the way

  21. anonymous
    • one year ago
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    ncr is combinations or not

  22. anonymous
    • one year ago
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    @Nourage and don't forget to multiply the answer with how much these teams gonna play with each other

  23. anonymous
    • one year ago
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    @Nourage do you know the formula of combinations

  24. anonymous
    • one year ago
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    please explain why you think combinations is relevant here...

  25. anonymous
    • one year ago
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    no i don t know hassan

  26. anonymous
    • one year ago
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    \[nCr=\frac{ n! }{ n!(n-r)! }\]

  27. anonymous
    • one year ago
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    plz hlp

  28. anonymous
    • one year ago
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    you know what is n and r?

  29. anonymous
    • one year ago
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    r radius

  30. anonymous
    • one year ago
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    or not

  31. anonymous
    • one year ago
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    did you look up the "handshake problem?" and did you see my drawing?

  32. anonymous
    • one year ago
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    combinations is ncr in the calc

  33. anonymous
    • one year ago
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    right or wrong

  34. anonymous
    • one year ago
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    hassan

  35. anonymous
    • one year ago
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    nope friend, n is the total number of teams and r is the team which will play just like two people will involve in a handshake two teams will participate to play a match,that's why we take r=2

  36. anonymous
    • one year ago
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    again, @Hassan3130 explain your reasoning for combinations! it's wrong and you're confusing the issue!

  37. anonymous
    • one year ago
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    i can t understand

  38. anonymous
    • one year ago
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    plz help

  39. anonymous
    • one year ago
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    \[\frac{ 4! }{ 2!2! }=\frac{ 24 }{4 }\]

  40. anonymous
    • one year ago
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    and wt is c

  41. anonymous
    • one year ago
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    i am saying to try for combination because i think it's easy to find but if you don't read much about this topic than you can follow what @pgpilot326 said

  42. anonymous
    • one year ago
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    ok but can u said to me how to solve it by ncr or npr in the calc

  43. anonymous
    • one year ago
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    @Hassan3130

  44. anonymous
    • one year ago
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    yes you can solve it from scientific caluclator

  45. anonymous
    • one year ago
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    how plz

  46. anonymous
    • one year ago
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    @Hassan3130

  47. anonymous
    • one year ago
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    but firstly you have to know the value of r and n

  48. anonymous
    • one year ago
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    r is 2 and n is4

  49. anonymous
    • one year ago
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    right

  50. anonymous
    • one year ago
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    yes

  51. anonymous
    • one year ago
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    then what i can i do on calc

  52. anonymous
    • one year ago
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    have you find it written on calculator"nCr"

  53. anonymous
    • one year ago
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    4n2

  54. anonymous
    • one year ago
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    4c2

  55. anonymous
    • one year ago
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    6

  56. anonymous
    • one year ago
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    yes right

  57. anonymous
    • one year ago
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    then 6*4 right

  58. anonymous
    • one year ago
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    yes absolutely right

  59. anonymous
    • one year ago
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    cause they will play with each other 4 times

  60. anonymous
    • one year ago
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    thank u @Hassan3130 and @pgpilot326

  61. anonymous
    • one year ago
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    your the best

  62. anonymous
    • one year ago
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    well done now i hope that you can solve questions like this

  63. anonymous
    • one year ago
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    sure hassan

  64. anonymous
    • one year ago
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    look at my 2nd response... see if that makes more sense. combination is valid

  65. anonymous
    • one year ago
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    thank u @pgpilot326

  66. anonymous
    • one year ago
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    i m a fan of u @Hassan3130 and pgpilot326

  67. anonymous
    • one year ago
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    bi hassan

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