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Can it be x x +2 and x+4?
It cannot be be x x +2 and x+4.. because if x=2 or any even number , then the remaining numbers cannot be odd integers.. I hope you understood...
nvm it cant
So what I suggest is.. take the numbers as: 2x - 1 , 2x + 1 and 2x + 3
here you asked about consecutive integers not odd integers so take x, x+1 , x+2 etc
let the 3 integers be x,x+1,x+2
got it ?same as before :)
yeah i do! : )
ok now do it your own :) if you want help tell after your work ok
im solving it rn, thank you.!
no problem ..
i distributed, so 5x + 10 = 3x +3x +3 -11 is that right?
no it's wrong
now solve it ..
no no its said 11 less than so it means 11 is subtracted from it
less means subtraction ok
yeah so 3 times the two integer is definitely bigger than 11 so how can you subtract that from 11??????
rather 11 is subtracted from 3 times the two integer
i got 18
i think i did my work wrong tho, I did 5x + 10 = 3x+3x+3-11 5x + 10 = 6x +3 -11 5x+10 = 6x -8 ??
okay got it :) but 5-6 would be -x so wouldnt it be a positive?
lol it would be x=18 by your method
bc of the two negatives right? lol
nvm i figured it out
5x+10=6x-8 6x-5x=10+8 x=18
is it the correct answer huh ?
18 is the correct answer
no pls don't confuse me any more
wellll if you switched the sides wouldnt it be -10 + -8? idk .. lol thanks though
nvm i think im just confusing myself
we are no switching sides we are combining the same terms
got it :) sorrry
5x+10 = 6x -8 5x-6x=-10-8 -x=-18 x=18