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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    If the 5 cards shown above are placed in a row so that [5] is never at either end, how many different arrangements are possible? The answer is 72...but I don't know how they got the answer...

  2. anonymous
    • one year ago
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    @ganeshie8

  3. anonymous
    • one year ago
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    [3] [2] [5] [9] [7]

  4. ganeshie8
    • one year ago
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    forget about the given restriction how many total ways can you arrange 5 cards in a row ?

  5. anonymous
    • one year ago
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    [3] [2] [5] [9] [7] every one of this is card

  6. anonymous
    • one year ago
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    how i solve it by calc plz

  7. ganeshie8
    • one year ago
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    |dw:1441093148752:dw|

  8. anonymous
    • one year ago
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    scientific calc

  9. ganeshie8
    • one year ago
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    initially you have 5 cards available, so you can choose the first card in 5 ways after that, you can choose the second card in 4 ways after that, you can choose the third card in 3 ways after that, you can choose the fourth card in 2 ways after that, you can choose the fifth card in 1 ways |dw:1441093246604:dw| so total number of ways of arranging 5 cards in a row = \(5*4*3*2*1 = 120\)

  10. anonymous
    • one year ago
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    card are 3 ,2,5,9,7

  11. ganeshie8
    • one year ago
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    \(120\) is the total number of arrangements with out any restrictions

  12. anonymous
    • one year ago
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    what of meaning of teamvier i m new in open study

  13. anonymous
    • one year ago
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    @ganeshie8

  14. anonymous
    • one year ago
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    The answer is 72...but I don't know how they got the answer not 120 i too keep the answer 120

  15. anonymous
    • one year ago
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    @ganeshie8

  16. ganeshie8
    • one year ago
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    120 is not the answer 120 is the total number of ways of arranging the given 5 cards with out any restrictions

  17. anonymous
    • one year ago
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    ok how i keep the answer

  18. anonymous
    • one year ago
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    72

  19. anonymous
    • one year ago
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    @@ganeshie8

  20. anonymous
    • one year ago
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    @ganeshie8

  21. ganeshie8
    • one year ago
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    lets find number of arrangements in which the first card is [5]

  22. ganeshie8
    • one year ago
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    if you fix the first card as [5], how many ways can you fill in remaining 4 positions ? |dw:1441093931611:dw|

  23. anonymous
    • one year ago
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    then wh

  24. anonymous
    • one year ago
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    24

  25. anonymous
    • one year ago
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    @ganeshie8

  26. ganeshie8
    • one year ago
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    Yes, so there are 24 ways in which the first card can be [5]

  27. ganeshie8
    • one year ago
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    similarly how many ways there such that last card is [5] ?

  28. anonymous
    • one year ago
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    24

  29. ganeshie8
    • one year ago
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    |dw:1441094262332:dw|

  30. ganeshie8
    • one year ago
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    so 24 ways in which first card is [5] and 24 ways in which last card is [5] thats 48 ways which we don't want

  31. ganeshie8
    • one year ago
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    subtract that from the total ways, 120

  32. anonymous
    • one year ago
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    72

  33. anonymous
    • one year ago
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    thanks man u are the best

  34. anonymous
    • one year ago
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    but what of meaning of teamvier i m new in open study

  35. anonymous
    • one year ago
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    @ganeshie8

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