counting question

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counting question

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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hlp
The number of arrangements with the designated card at the left end is 4! The number of arrangements with the designated card at the right end is 4! Therefore the number of arrangements that are not allowed is (4! + 4!). The total number of arrangements with no restrictions is 5!. Therefore the number of arrangements with the designated card not at either end is given by: 5! - (4! + 4!) = you can calculate.

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Other answers:

can u tell me how to solve by scientific calc@kropot72
npr or ncr
and how
Does your calculator have a factorial function, labelled x! ?|dw:1441097323742:dw|
then wt
Then enter: 5 x! - (4 x! + 4 x!) =
oh ya i understand
but why u do only 4 +4 not 5+5
ok i
understand
but can i do it by npr or ncr
5P5 - (4P4 + 4P4) =
ok thnks man u are the best i ll be fan of u
You're welcome :)

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