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anonymous

  • one year ago

Can Someone Help Me W/ This -Giving Medals-

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  1. anonymous
    • one year ago
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    here is the pic

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  2. anonymous
    • one year ago
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    \[2^{M} = 1/8\]

  3. anonymous
    • one year ago
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    this rules will help you, \[u^v=e^{v \times \ln u}\] \[\ln({e^x})=x\] \[\ln(1/a)=-\ln(a)\]

  4. phi
    • one year ago
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    one idea to try (and for these questions, it probably always works) is to see if you can multiply the base (the 2 in this problem) times itself, and get the number 8 2*2*2= 8 that means you can write it as \(2^3\) using the "short-hand way" (with exponents) \[ 2^m= \frac{1}{2^3} \] that looks promising , except the right side is "upside-down" you can "flip" the fraction *if you make the exponent negative* in other words \[ \frac{1}{2^3} = \frac{2^{-3}}{1} = 2^{-3} \] so now it is \[ 2^m = 2^{-3} \] now pattern match... what should m be to make both sides look the same ?

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