## anonymous one year ago Can Someone Help Me W/ This -Giving Medals-

1. anonymous

here is the pic

2. anonymous

$2^{M} = 1/8$

3. anonymous

this rules will help you, $u^v=e^{v \times \ln u}$ $\ln({e^x})=x$ $\ln(1/a)=-\ln(a)$

4. phi

one idea to try (and for these questions, it probably always works) is to see if you can multiply the base (the 2 in this problem) times itself, and get the number 8 2*2*2= 8 that means you can write it as $$2^3$$ using the "short-hand way" (with exponents) $2^m= \frac{1}{2^3}$ that looks promising , except the right side is "upside-down" you can "flip" the fraction *if you make the exponent negative* in other words $\frac{1}{2^3} = \frac{2^{-3}}{1} = 2^{-3}$ so now it is $2^m = 2^{-3}$ now pattern match... what should m be to make both sides look the same ?