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anonymous
 one year ago
Can Someone Help Me W/ This Giving Medals
anonymous
 one year ago
Can Someone Help Me W/ This Giving Medals

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this rules will help you, \[u^v=e^{v \times \ln u}\] \[\ln({e^x})=x\] \[\ln(1/a)=\ln(a)\]

phi
 one year ago
Best ResponseYou've already chosen the best response.0one idea to try (and for these questions, it probably always works) is to see if you can multiply the base (the 2 in this problem) times itself, and get the number 8 2*2*2= 8 that means you can write it as \(2^3\) using the "shorthand way" (with exponents) \[ 2^m= \frac{1}{2^3} \] that looks promising , except the right side is "upsidedown" you can "flip" the fraction *if you make the exponent negative* in other words \[ \frac{1}{2^3} = \frac{2^{3}}{1} = 2^{3} \] so now it is \[ 2^m = 2^{3} \] now pattern match... what should m be to make both sides look the same ?
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