iwanttogotostanford
  • iwanttogotostanford
QUICK ALGEBRA QUESTION< NEED HELP_Expand the 5th root of x into an exponent with a fraction, 1/5 In the exponent of x, multiply 7 times this value In the exponent of x, Multiply the result times 3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
what O.o (, )_( ')
iwanttogotostanford
  • iwanttogotostanford
SORRY NOT THAT : Describe how to transform the quantity of the fifth root of x to the seventh power, to the third powerinto an expression with a rational exponent. Make sure you respond with complete sentences.@Dyron_Libaunask
iwanttogotostanford
  • iwanttogotostanford
\[(\sqrt[5]x{^7})^3\]

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anonymous
  • anonymous
@THEHELPER123
iwanttogotostanford
  • iwanttogotostanford
Thats the equation
anonymous
  • anonymous
he2 better at explenatiion2 than ii am
iwanttogotostanford
  • iwanttogotostanford
if he doesn't show up can you still just explain step by step please?
anonymous
  • anonymous
dumb iit down, what do you need for an awncer?
iwanttogotostanford
  • iwanttogotostanford
i need basically a short paragraph on explaining how to solve this problem
anonymous
  • anonymous
ok
anonymous
  • anonymous
pemdas (5√x7)3 ... XC ii 2uck at explenatiion2
anonymous
  • anonymous
2orry, ii can get you an awncer two iit but iit2 allmental math and ii dont do well whiith 2howiing work
anonymous
  • anonymous
wiith*
iwanttogotostanford
  • iwanttogotostanford
ok
anonymous
  • anonymous
ive actually never learned about this yet
anonymous
  • anonymous
@phi
anonymous
  • anonymous
wow O.O
anonymous
  • anonymous
ik im not good a exponets i never heard of the 5th root
iwanttogotostanford
  • iwanttogotostanford
its hard i don't know how to do it
phi
  • phi
\[ \left(\sqrt[5]{x^7}\right)^3 \] replace the 5th root with the exponent 1/5 \[ \left((x^7)^\frac{1}{5}\right)^3 \]
iwanttogotostanford
  • iwanttogotostanford
ok
iwanttogotostanford
  • iwanttogotostanford
now what
iwanttogotostanford
  • iwanttogotostanford
? @phi
phi
  • phi
work from the inside out using this rule \[ \left(a^b\right)^c = a^{bc} \]
phi
  • phi
do you understand how to interpret that rule?

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