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anonymous

  • one year ago

Need help with five Algebra 2 questions! Please help me. I'm never able to get help on this website hardly ever.

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    any particular question?

  3. misty1212
    • one year ago
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    ??

  4. anonymous
    • one year ago
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    Yes! @misty1212

  5. misty1212
    • one year ago
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    best to post a specific question

  6. anonymous
    • one year ago
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    let me pull them up!

  7. anonymous
    • one year ago
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    Okay my first question is this: What is the graph of the absolute value equation? y = /x/ -9

  8. misty1212
    • one year ago
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    do you know what \(y=|x|\) looks like? that is the basic starting point

  9. anonymous
    • one year ago
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    Not really. I've been having a lot of trouble with graphing :(

  10. misty1212
    • one year ago
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    it looks like a V |dw:1441118922280:dw|

  11. misty1212
    • one year ago
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    to the right of zero it is the line \(y=x\) to the left it is \(y=-x\)

  12. anonymous
    • one year ago
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    Okay I thought so. Can the V's placement move up and down on the graph?

  13. misty1212
    • one year ago
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    when you subtract 9 outside, it moves it down 9 units

  14. anonymous
    • one year ago
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    Thats what I was about to draw.

  15. misty1212
    • one year ago
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    and output is 9 less than \(y=|x|\)

  16. misty1212
    • one year ago
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    |dw:1441119016232:dw|

  17. anonymous
    • one year ago
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    Okay so when you have y = /x/ will it always look like a V?

  18. misty1212
    • one year ago
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    lol yeah it never changes

  19. anonymous
    • one year ago
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    And then the number at the end of the equation is where you place it.

  20. anonymous
    • one year ago
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    Sorry... Math is not my strongest subject.

  21. misty1212
    • one year ago
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    no problem

  22. misty1212
    • one year ago
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    if it was say \(y=|x|+2\) it would be up 2 units

  23. anonymous
    • one year ago
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    Do you have time to help me with a few more?

  24. misty1212
    • one year ago
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    sure

  25. anonymous
    • one year ago
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    Thank you so much!

  26. anonymous
    • one year ago
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    What is the graph of the absolute value equation? y = /x+4/

  27. misty1212
    • one year ago
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    ok this one is a bit different because FIRST you add 4 THEN take the absolute value

  28. misty1212
    • one year ago
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    that shifts the V 4 units to the LEFT`

  29. misty1212
    • one year ago
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    |dw:1441119337575:dw|

  30. misty1212
    • one year ago
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    don't be confused by going to the left think of it this way the smallest the absolute value can be is zero, so if \(x=-4\) then \(y=|-4+4|=|0|=0\)

  31. anonymous
    • one year ago
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    And its positive right so wouldn't it be to the right?

  32. anonymous
    • one year ago
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    Oh! Your reply came in late so I didn't see it! I got it!

  33. misty1212
    • one year ago
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    no for the reason i wrote above don't forget the order in which you do things here first add 4, then take the absolute value if \(x=4\) then \(y=|4+4|=8\) not 0

  34. anonymous
    • one year ago
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    Yes, I understand. I didn't see what you said before I replied.

  35. misty1212
    • one year ago
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    it is more general than just for the absolute value compared to \(y=f(x)\) the graph of \((y=f(x+4)\) would be shifted to the LEFT 4

  36. anonymous
    • one year ago
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    Okay! I got it :) So the graph would have the v shifted to the left 4

  37. misty1212
    • one year ago
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    yes

  38. anonymous
    • one year ago
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    Awesome. You are so much help!

  39. misty1212
    • one year ago
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    \[\color\magenta\heartsuit\]

  40. anonymous
    • one year ago
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    :) cute!

  41. misty1212
    • one year ago
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    quick quiz how would \[y=|x+2|-3\] be shifted?

  42. anonymous
    • one year ago
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    okay one second

  43. anonymous
    • one year ago
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    y = /x+2/ -3 = /0/ -3

  44. misty1212
    • one year ago
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    your answer should be left or right so many units, up or down so many units

  45. anonymous
    • one year ago
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    Wait... I don't think I'm doing it right

  46. anonymous
    • one year ago
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    |dw:1441119892914:dw|

  47. misty1212
    • one year ago
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    \[\huge y=|x\overbrace{+2}^{\text{left 2}}|\overbrace{-3}^{\text{down 3}}\]

  48. anonymous
    • one year ago
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    okay let me graph it

  49. anonymous
    • one year ago
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    |dw:1441120014777:dw|

  50. misty1212
    • one year ago
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    pretty good

  51. misty1212
    • one year ago
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    a bit off since it does not go through \((0,0)\)

  52. anonymous
    • one year ago
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    We just learned these in class today

  53. anonymous
    • one year ago
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    Yeah it's hard to draw it on here

  54. misty1212
    • one year ago
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    |dw:1441120134731:dw|

  55. misty1212
    • one year ago
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    close enough

  56. anonymous
    • one year ago
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    I have two more if you don't mind.

  57. anonymous
    • one year ago
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    I want to try them first and then could you check my answers?

  58. misty1212
    • one year ago
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    \[\huge y=|x\overbrace{-4}^{\text{ right 4}}|\overbrace{+2}^{\text{up 2}}\]

  59. misty1212
    • one year ago
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    sure

  60. anonymous
    • one year ago
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    What is the graph of the absolute value equation? y = /x+3/ -4

  61. misty1212
    • one year ago
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    ok pretty close to the last one we did

  62. anonymous
    • one year ago
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    Yes.

  63. anonymous
    • one year ago
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    |dw:1441120404739:dw|

  64. misty1212
    • one year ago
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    excellent

  65. anonymous
    • one year ago
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    |dw:1441120491775:dw|

  66. anonymous
    • one year ago
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    More like this though

  67. anonymous
    • one year ago
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    Okay the next one has a fraction in it.

  68. misty1212
    • one year ago
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    i hate fractions

  69. anonymous
    • one year ago
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    What is the absolute value of the equation? y = 1/2 /x/

  70. anonymous
    • one year ago
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    Me too

  71. misty1212
    • one year ago
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    it can't really ask "what is the absolute value" right? maybe graph it ?

  72. anonymous
    • one year ago
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    lol! I left that out! it is graphing

  73. misty1212
    • one year ago
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    yeah that looks the the original V except it is wider

  74. anonymous
    • one year ago
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    You're graphing -1/2 /x/

  75. misty1212
    • one year ago
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    |dw:1441120715407:dw|

  76. anonymous
    • one year ago
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    |dw:1441120740635:dw|

  77. misty1212
    • one year ago
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    oh is it \[y=-\frac{1}{2}|x|\]?

  78. anonymous
    • one year ago
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    Yes Ma'am.

  79. anonymous
    • one year ago
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    So wouldn't it be |dw:1441120824712:dw| ?

  80. misty1212
    • one year ago
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    then your are right (ma'am, lol)

  81. anonymous
    • one year ago
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    :)

  82. anonymous
    • one year ago
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    Okay there's a bonus question on my homework that has a graph like this: |dw:1441120904317:dw|

  83. misty1212
    • one year ago
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    where does it sit ?|dw:1441120941672:dw|

  84. anonymous
    • one year ago
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    The choices that they give you are: y = 7/x+8/-4 y =-7/x-8/+4 y =-7/x+8/-4

  85. anonymous
    • one year ago
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    And y = -7/x-8/-4

  86. anonymous
    • one year ago
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    That's what it looks like?

  87. misty1212
    • one year ago
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    no that was wrong \((-8,-4)\)

  88. anonymous
    • one year ago
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    Yes.

  89. anonymous
    • one year ago
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    (-8, -4)

  90. misty1212
    • one year ago
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    so it is going to look like \[y=a|x+8|-8\]

  91. misty1212
    • one year ago
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    and since it opens down \(a\) is a negative number

  92. anonymous
    • one year ago
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    I think it's C

  93. misty1212
    • one year ago
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    so probably C ( it is almost always C)

  94. anonymous
    • one year ago
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    When in doubt Charlie out! (Thats what my mom says)

  95. misty1212
    • one year ago
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    your mom is smart

  96. anonymous
    • one year ago
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    Okay I finished! Let's see what I got!

  97. misty1212
    • one year ago
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    lol yeah let's C

  98. anonymous
    • one year ago
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    I made a 100!

  99. misty1212
    • one year ago
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    yay!!

  100. anonymous
    • one year ago
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    Thank you sooooooo much!

  101. misty1212
    • one year ago
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    \[\huge \color\magenta\heartsuit\]

  102. anonymous
    • one year ago
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    <3

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