Someone please help me step by step i've been stuck on this and i want to learn
1. D = p(3 + nr) solve for r

- anonymous

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- Hero

@milli_lovesyouu begin by dividing both sides by p.

- anonymous

D/p = (3+nr) ?

- Hero

Very good. Now 3 + nr isn't being multiplied by anything anymore so the parentheses are no longer needed. You can remove them.

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- anonymous

okay so then i have to get rid of the n right?

- Hero

The next step after removing the parentheses is to subtract 3 from both sides.

- anonymous

-3d/p = nr ?

- Hero

The right side is correct, but the left side is incorrect. You wrote -3 as multiplying d/p, but what you actually what to do is subtract 3 from d/p. Have an idea of how to write that?

- anonymous

no idea :(

- Hero

How do you write six minus 3?

- anonymous

6 - 3

- anonymous

3 - d/p ?

- Hero

How do you write one-third minus 3?

- Hero

Very good. How do you write d/p minus three?

- anonymous

d/p - 3 = nr?

- Hero

Yes, correct. Subtracting 3 from d/p means the same as d/p minus three. You should pay very close attention to the way math phrases are worded. Now the last step is important and I want you to get it right. First I want you to place everything on the left side in parentheses.

- anonymous

no idea im sorry i tried on paper but it didnt make sense to me

- Hero

Type it first in here. I'll explain it later. Just simply place the expression on the left side within a set of parentheses.

- anonymous

d/p is outside the ( ) right ?

- Hero

The entire expression on the left side, put parentheses around it.

- anonymous

(d/p - 3) = nr
then, multiple both sides by n?

- Hero

The expression above is correct as written. Notice that n is being multiplied by r. So to undo that, we have to actually perform an inverse operation. DIVISION. Divide both sides by n.

- Hero

The final expression is going to look kind of awkward, I know, but no one says the equations have to look pretty.

- Hero

You're changing it to something else. When you put the expression in parentheses, YOU CANNOT alter it. It's ONE expression. You divide the entire expression by n.

- anonymous

okay, so it'll be (d/p - 3) / n = r ?

- Hero

Exactly correct.

- Hero

And if you're confused about how that looks on paper, it will look like this:
\(\dfrac{\dfrac{d}{p} - 3}{n} = r\)

- anonymous

thats my answer?

- Hero

Yes

- anonymous

these are my answer choices though ?

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- anonymous

@Hero

- Hero

It's unfortunate that they have done that, because now they basically want you to re-write it in a different form.

- anonymous

can you help me? :( please

- Hero

No wonder you were confused about how to write the final form.

- anonymous

yea i was looking at my book and other examples but i couldn't figure it out for nothing

- Hero

It will be more difficult to explain based on the manipulation necessary to re-write it in the proper form.

- anonymous

its okay ill just email my teacher about it i guess

- anonymous

Thank you so much for all your help!

- Hero

Why do you need to email your teacher about it? Have you given up on solving this?

- anonymous

what other way can i write this?

- anonymous

i was looking at answer choice a at first

- Hero

The next step is to first re-write it this way:
\(\dfrac{1}{n}\left(\dfrac{d}{p} - 3\right) = r\)
Believe it or not, the expression on the left is equivalent to the expression we got for our initial answer.

- Hero

Next, you distribute \(\dfrac{1}{n}\) over \(\dfrac{d}{p} - 3\) to get \(\dfrac{d}{pn} - \dfrac{3}{n}\)

- Hero

Afterwards multiply \(\dfrac{3}{n}\) by \(\dfrac{p}{p}\) to get \(\dfrac{3p}{p}\)
So the expression on the left now looks like
\(\dfrac{d}{pn} - \dfrac{3p}{pn}\

- Hero

Notice the denominators are the same so we can combine the expression to get:
\(\dfrac{d - 3p}{pn} = r\)

- anonymous

So, A right?

- Hero

A is correct but the important thing to know is how to get A. You can't get it by eyeballing it and you should never try to guess with problems like these.

- anonymous

yea, i like explanations so i learn because these problems are on my next test :( im in college intermediate Algebra

- anonymous

Thank you so much!!!!

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