anonymous
  • anonymous
What is the value of the expression 8–2? A.–16 B. 1/64 C. 1/16 D.64
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SOLVED
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chestercat
  • chestercat
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just_one_last_goodbye
  • just_one_last_goodbye
Hey you should post this in math ^_^
anonymous
  • anonymous
@mathmath333 @Tazmaniadevil
just_one_last_goodbye
  • just_one_last_goodbye
@MadisonEmery is that 8 take away 2?

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anonymous
  • anonymous
ya
just_one_last_goodbye
  • just_one_last_goodbye
give me a sec
just_one_last_goodbye
  • just_one_last_goodbye
I really dont see how the answer choices are relevant really sorry im no help ;-;
just_one_last_goodbye
  • just_one_last_goodbye
@pooja195 please help my friend ^_^
pooja195
  • pooja195
If this is a square 8^-2 then all you need to do is -8 x -8
anonymous
  • anonymous
thx
pooja195
  • pooja195
:)
anonymous
  • anonymous
so it would be D
just_one_last_goodbye
  • just_one_last_goodbye
oh I didn't see the exponent
just_one_last_goodbye
  • just_one_last_goodbye
thats why i asked if this was a subtraction problem not \[8^{-2}\]
anonymous
  • anonymous
so it would be D @pooja195
just_one_last_goodbye
  • just_one_last_goodbye
Yes @MadisonEmery a negative times a negative is a positive and 8 x 8 is 64
anonymous
  • anonymous
this is wrong
anonymous
  • anonymous
!!!!!@pooja195 !!!!!! you are wrong thats not how it works
pooja195
  • pooja195
?
anonymous
  • anonymous
this should be: 1/8^-2
anonymous
  • anonymous
therefore 1/64
anonymous
  • anonymous
This is not multiplication, this is an exponent. With negative exponents you put the 8^-2 under 1 like this: 1/8^-2 the answer is NOT 64 the answer is 1/64
anonymous
  • anonymous
anonymous
  • anonymous
Please look
pooja195
  • pooja195
well I was taught diffrently.
just_one_last_goodbye
  • just_one_last_goodbye
Im afraid Twistnflip is correct. 8^-2 = 1/ 8 * 8 = 1/8^2 = 1/64
just_one_last_goodbye
  • just_one_last_goodbye
sorry Pooja ;-; nothing personal
pooja195
  • pooja195
Also the problem was written wrongly.
just_one_last_goodbye
  • just_one_last_goodbye
^ very
pooja195
  • pooja195
But i accept my mistake :)
anonymous
  • anonymous
its ok, just wanted to make sure she didn't get it wrong
just_one_last_goodbye
  • just_one_last_goodbye
Shes so mature ^-^

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