A community for students.
Here's the question you clicked on:
 0 viewing
mathmath333
 one year ago
A mixed double tennis game is to be played between two teams
(each team consists of one male and one female ).There are
four married couples . No team is to consist of a husband and
{his wife. What is the maximum number of games that can be played.
mathmath333
 one year ago
A mixed double tennis game is to be played between two teams (each team consists of one male and one female ).There are four married couples . No team is to consist of a husband and {his wife. What is the maximum number of games that can be played.

This Question is Closed

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{A mixed double tennis game is to be played between two teams }\hspace{.33em}\\~\\ & \normalsize \text{(each team consists of one male and one female ).There are }\hspace{.33em}\\~\\ & \normalsize \text{four married couples . No team is to consist of a husband and }\hspace{.33em}\\~\\ & \normalsize \text{his wife. What is the maximum number of games that can be played. }\hspace{.33em}\\~\\ & a.)\ 12 \hspace{.33em}\\~\\ & b.)\ 21 \hspace{.33em}\\~\\ & c.)\ 36 \hspace{.33em}\\~\\ & d.)\ 42 \hspace{.33em}\\~\\ \end{align}}\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Husband is A, B, C, D Wife is 1, 2, 3, 4 Married couples are: A1, B2, C3, D4 For each line below, the pair in the first column can play a match with each pair following it. For example, for the first line below, there can be matches: A2 vs B1, A2 vs B3, A2 vs B4, etc. A2 B1 B3 B4 C1 C4 D1 D3 A3 B1 B4 C1 C2 C4 D1 D2 A4 B1 B3 C1 C2 D1 D2 D3 It looks like 21 different matches.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0answer is given is 42

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0i think there are 12 pairs that can play matches with each other

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0is he still typing

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Sorry. I though all other combinations were repeats. Let me do this again. Here are all possible matches, but some are repeats. A2 B1 B3 B4 C1 C4 D1 D3 A3 B1 B4 C1 C2 C4 D1 D2 A4 B1 B3 C1 C2 D1 D2 D3 B1 A2 A3 A4 C2 C4 D2 D3 B3 A2 A4 C1 C2 C4 D1 D2 B4 A2 A3 C1 C2 D1 D2 D3 C1 A2 A3 A4 B3 B4 D2 D3 C2 A3 A4 B1 B3 B4 D1 D3 C4 A2 A3 B1 B3 D1 D2 D3 D1 A2 A3 A4 B3 B4 C2 C4 D2 A3 A4 B1 B3 B4 C1 C4 D3 A2 A4 B1 B4 C1 C2 C4

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Now we eliminate repeats. A2 B1 B3 B4 C1 C4 D1 D3 A3 B1 B4 C1 C2 C4 D1 D2 A4 B1 B3 C1 C2 D1 D2 D3 B1 C2 C4 D2 D3 B3 C1 C2 C4 D1 D2 B4 C1 C2 D1 D2 D3 C1 D2 D3 C2 D1 D3 C4 D1 D2 D3 Now the total is 42.

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.14 man and 4 women can form 16 teams. 4 teams are forbidden since there are 4 married couples. There are 12C2=66 unique ways of choosing 2 elements from a set with 12 elements. Therefore 12 teams can have 12C2=66 ways of matching and game.

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.1The set of available matches are: {{1, 2}, {1, 3}, {1, 4}, {1, 5}, {1, 6}, {1, 7}, {1, 8}, {1, 9}, {1,10}, {1, 11}, {1, 12}, {2, 3}, {2, 4}, {2, 5}, {2, 6}, {2, 7}, {2, 8}, {2, 9}, {2, 10}, {2, 11}, {2, 12}, {3, 4}, {3, 5}, {3, 6}, {3, 7}, {3, 8}, {3, 9}, {3, 10}, {3, 11}, {3, 12}, {4, 5}, {4, 6}, {4, 7}, {4, 8}, {4, 9}, {4, 10}, {4, 11}, {4, 12}, {5, 6}, {5, 7}, {5, 8}, {5, 9}, {5, 10}, {5, 11}, {5, 12}, {6, 7}, {6, 8}, {6, 9}, {6, 10}, {6, 11}, {6, 12}, {7, 8}, {7, 9}, {7, 10}, {7, 11}, {7, 12}, {8, 9}, {8, 10}, {8, 11}, {8, 12}, {9, 10}, {9, 11}, {9, 12}, {10, 11}, {10, 12}, {11, 12}}

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.1The size of the set is 66.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0mathstudent's answer is correct, but i m looking for a short answer rather than listing all as mathstudent did.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@thomas5267 only problem is that A2 cannot play A3. In your scheme, these are indeed different teams but they cannot play each other. For a given team, it has only 6 other teams against which it can compete. then you have to count repeats as well.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops, 7 other teams against which it can compete

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3@thomas5267 The problem states that a man and his wife cannot form a team, so you can't form 16 teams.

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.1Computer says there are 42 combinations. I calculated it using brute force.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.