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warpedkitten

  • one year ago

A chemical reaction between X and Y forms C according to the reaction below. The data for three trials to measure the rate of this reaction are also given. X + 2Y → C

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  1. warpedkitten
    • one year ago
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  2. JoannaBlackwelder
    • one year ago
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    Can you write the rate law expression for the first trial?

  3. warpedkitten
    • one year ago
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    No?

  4. JoannaBlackwelder
    • one year ago
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    This is the general form:|dw:1441073645037:dw|

  5. JoannaBlackwelder
    • one year ago
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    Try plugging in what you know from the first trial.

  6. warpedkitten
    • one year ago
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    So it'd be R = k[0.03][0.005]^3? But what do I do with that?

  7. JoannaBlackwelder
    • one year ago
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    You plugged in the concentrations correctly, but the exponents are not the coefficients of the balanced reaction. And plug in the rate given as well.

  8. JoannaBlackwelder
    • one year ago
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    Leave the coefficients as a and b for now. I'll help you with the tricky step. :-)

  9. warpedkitten
    • one year ago
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    I'm still completely confused.

  10. JoannaBlackwelder
    • one year ago
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    Ok, the info from the first trial gives us 4.3x10^-4=k(0.03)^a(0.005)^b Do you see how I plugged that in so far?

  11. warpedkitten
    • one year ago
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    Yes.

  12. JoannaBlackwelder
    • one year ago
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    Cool. You try for the second trial, then I will show you what to do with them.

  13. warpedkitten
    • one year ago
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    1.72x10^-3=k(0.03)^a(0.01)]^b

  14. JoannaBlackwelder
    • one year ago
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    Sweet, now we take those and divide them.

  15. JoannaBlackwelder
    • one year ago
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    |dw:1441041314787:dw|

  16. JoannaBlackwelder
    • one year ago
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    Then we cancel|dw:1441041548845:dw|

  17. JoannaBlackwelder
    • one year ago
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    Does that step make sense?

  18. warpedkitten
    • one year ago
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    Yes

  19. JoannaBlackwelder
    • one year ago
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    Great! Can you solve for b from here?

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