What is the value of the expression 4/2^-2? A. ½ B. 1 C. 8 D. 16

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What is the value of the expression 4/2^-2? A. ½ B. 1 C. 8 D. 16

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Other answers:

plz help me
Show your work. Stop tagging the world.
im trying im stuck
  • phi
do you know how to "flip" \[ \frac{1}{2^{-2} }\] ?
yes
See, you could have shown that.
i did
it is 4/2^-2
  • phi
what do you get when you flip \[ \frac{1}{2^{-2}} \]?
No, you wrote the problem statement. You did not show that you knew how to "flip" negative exponents. You could have shown that.
ok it is
i for got show me plz
  • phi
the "rule" is flip the fraction (bottom becomes top and vice versa) *and* change the exponent by multiplying the exponent by -1
  • phi
can you do that for \[ \frac{1}{2^{-2}} \]
  • phi
here is an example \[ \frac{1}{5^3}= \frac{5^{-3}}{1}\]
ok
  • phi
do it in two steps: 1) first, can you write the "flipped" version of 1/2^(-2) ?
k
yes
  • phi
can you post step 1) flip 1/2^(-2)
\[\frac{ 1 }{ 2^3 }\]
-3
  • phi
start with \[ \frac{1}{2^{-2}} \] now make the bottom (the \( 2^{-2}\) ) the top and make the top (the 1) the new bottom what do you get ?
it is the same
  • phi
if you had \[ \frac{a}{b}\] the flipped version is \[ \frac{b}{a} \]
im sorry somthing so simple is hard for me
  • phi
ok, practice with this x/y what is that flipped?
x/y-y?
  • phi
x/y flipped becomes y/x try c/d what is that flipped?
oooo d/c
  • phi
yes. now try 3/2 flipped is ?
2/3
  • phi
yes now this one (4*2)/(5*6) flip that
2*4/6*5
1/(2-^2)
  • phi
try 1/(2*3) flip that
humm 1/(3*2)
  • phi
no, (2*3)/1 just like a/b becomes b/a c/d becomes d/c x/y becomes y/x (2*3)/(4*5) becomes (4*5)/(2*3) do you see the pattern ?
yes
  • phi
now try 1/(2*3)
sorry
ok (2*3)/1
  • phi
yes. now use that same idea on 1/(2^-2) flip this one
(2_^2)/1
  • phi
(2^-2)/1
o woops
  • phi
now when we flip things they change 1/2 is different from 2/1 but if we have 1/(2^-2) and flip it to 2^-2/1 then *change the exponent* so that we have 2^2/1 it turns out that \[ \frac{1}{2^{-2}} = \frac{2^2}{1} \]
  • phi
so we do two things: flip and *change the exponent*
ok
humm
  • phi
now your problem is \[ 4 \cdot \frac{1}{2^{-2}} \] and 1/2^-2 is 2^2, so it is now \[ 4 \cdot 2^2 \]
  • phi
2^2 means 2*2 4* 2^2 means 4*2*2
ok nvm i got it u r just beating around the boosh sorry i figured it out thx thow
  • phi
you should get 16

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