anonymous
  • anonymous
What is the value of the expression 4/2^-2? A. ½ B. 1 C. 8 D. 16
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@Studyhelp_00002
anonymous
  • anonymous
@GracieBugg
anonymous
  • anonymous
@Kitten_is_back

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More answers

anonymous
  • anonymous
@amberosales
anonymous
  • anonymous
plz help me
tkhunny
  • tkhunny
Show your work. Stop tagging the world.
anonymous
  • anonymous
im trying im stuck
phi
  • phi
do you know how to "flip" \[ \frac{1}{2^{-2} }\] ?
anonymous
  • anonymous
yes
tkhunny
  • tkhunny
See, you could have shown that.
anonymous
  • anonymous
i did
anonymous
  • anonymous
it is 4/2^-2
phi
  • phi
what do you get when you flip \[ \frac{1}{2^{-2}} \]?
tkhunny
  • tkhunny
No, you wrote the problem statement. You did not show that you knew how to "flip" negative exponents. You could have shown that.
anonymous
  • anonymous
ok it is
anonymous
  • anonymous
i for got show me plz
phi
  • phi
the "rule" is flip the fraction (bottom becomes top and vice versa) *and* change the exponent by multiplying the exponent by -1
phi
  • phi
can you do that for \[ \frac{1}{2^{-2}} \]
phi
  • phi
here is an example \[ \frac{1}{5^3}= \frac{5^{-3}}{1}\]
anonymous
  • anonymous
ok
phi
  • phi
do it in two steps: 1) first, can you write the "flipped" version of 1/2^(-2) ?
anonymous
  • anonymous
k
anonymous
  • anonymous
yes
phi
  • phi
can you post step 1) flip 1/2^(-2)
anonymous
  • anonymous
\[\frac{ 1 }{ 2^3 }\]
anonymous
  • anonymous
-3
phi
  • phi
start with \[ \frac{1}{2^{-2}} \] now make the bottom (the \( 2^{-2}\) ) the top and make the top (the 1) the new bottom what do you get ?
anonymous
  • anonymous
it is the same
phi
  • phi
if you had \[ \frac{a}{b}\] the flipped version is \[ \frac{b}{a} \]
anonymous
  • anonymous
im sorry somthing so simple is hard for me
phi
  • phi
ok, practice with this x/y what is that flipped?
anonymous
  • anonymous
x/y-y?
phi
  • phi
x/y flipped becomes y/x try c/d what is that flipped?
anonymous
  • anonymous
oooo d/c
phi
  • phi
yes. now try 3/2 flipped is ?
anonymous
  • anonymous
2/3
phi
  • phi
yes now this one (4*2)/(5*6) flip that
anonymous
  • anonymous
2*4/6*5
anonymous
  • anonymous
1/(2-^2)
phi
  • phi
try 1/(2*3) flip that
anonymous
  • anonymous
humm 1/(3*2)
phi
  • phi
no, (2*3)/1 just like a/b becomes b/a c/d becomes d/c x/y becomes y/x (2*3)/(4*5) becomes (4*5)/(2*3) do you see the pattern ?
anonymous
  • anonymous
yes
phi
  • phi
now try 1/(2*3)
anonymous
  • anonymous
sorry
anonymous
  • anonymous
ok (2*3)/1
phi
  • phi
yes. now use that same idea on 1/(2^-2) flip this one
anonymous
  • anonymous
(2_^2)/1
phi
  • phi
(2^-2)/1
anonymous
  • anonymous
o woops
phi
  • phi
now when we flip things they change 1/2 is different from 2/1 but if we have 1/(2^-2) and flip it to 2^-2/1 then *change the exponent* so that we have 2^2/1 it turns out that \[ \frac{1}{2^{-2}} = \frac{2^2}{1} \]
phi
  • phi
so we do two things: flip and *change the exponent*
anonymous
  • anonymous
ok
anonymous
  • anonymous
humm
phi
  • phi
now your problem is \[ 4 \cdot \frac{1}{2^{-2}} \] and 1/2^-2 is 2^2, so it is now \[ 4 \cdot 2^2 \]
phi
  • phi
2^2 means 2*2 4* 2^2 means 4*2*2
anonymous
  • anonymous
ok nvm i got it u r just beating around the boosh sorry i figured it out thx thow
phi
  • phi
you should get 16

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