What is the value of the expression 4/2^-2?
A.
½
B.
1
C.
8
D.
16

- anonymous

What is the value of the expression 4/2^-2?
A.
½
B.
1
C.
8
D.
16

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- anonymous

@Studyhelp_00002

- anonymous

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- anonymous

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## More answers

- anonymous

@amberosales

- anonymous

plz help me

- tkhunny

Show your work. Stop tagging the world.

- anonymous

im trying im stuck

- phi

do you know how to "flip"
\[ \frac{1}{2^{-2} }\]
?

- anonymous

yes

- tkhunny

See, you could have shown that.

- anonymous

i did

- anonymous

it is 4/2^-2

- phi

what do you get when you flip
\[ \frac{1}{2^{-2}} \]?

- tkhunny

No, you wrote the problem statement. You did not show that you knew how to "flip" negative exponents. You could have shown that.

- anonymous

ok it is

- anonymous

i for got show me plz

- phi

the "rule" is flip the fraction (bottom becomes top and vice versa)
*and*
change the exponent by multiplying the exponent by -1

- phi

can you do that for
\[ \frac{1}{2^{-2}} \]

- phi

here is an example
\[ \frac{1}{5^3}= \frac{5^{-3}}{1}\]

- anonymous

ok

- phi

do it in two steps:
1) first, can you write the "flipped" version of 1/2^(-2) ?

- anonymous

k

- anonymous

yes

- phi

can you post step 1) flip 1/2^(-2)

- anonymous

\[\frac{ 1 }{ 2^3 }\]

- anonymous

-3

- phi

start with
\[ \frac{1}{2^{-2}} \]
now make the bottom (the \( 2^{-2}\) ) the top
and make the top (the 1) the new bottom
what do you get ?

- anonymous

it is the same

- phi

if you had
\[ \frac{a}{b}\]
the flipped version is
\[ \frac{b}{a} \]

- anonymous

im sorry somthing so simple is hard for me

- phi

ok, practice with this
x/y
what is that flipped?

- anonymous

x/y-y?

- phi

x/y flipped becomes y/x
try c/d
what is that flipped?

- anonymous

oooo d/c

- phi

yes. now try
3/2 flipped is ?

- anonymous

2/3

- phi

yes
now this one
(4*2)/(5*6)
flip that

- anonymous

2*4/6*5

- anonymous

1/(2-^2)

- phi

try
1/(2*3)
flip that

- anonymous

humm
1/(3*2)

- phi

no, (2*3)/1
just like a/b becomes b/a
c/d becomes d/c
x/y becomes y/x
(2*3)/(4*5) becomes (4*5)/(2*3)
do you see the pattern ?

- anonymous

yes

- phi

now try
1/(2*3)

- anonymous

sorry

- anonymous

ok (2*3)/1

- phi

yes.
now use that same idea on
1/(2^-2)
flip this one

- anonymous

(2_^2)/1

- phi

(2^-2)/1

- anonymous

o woops

- phi

now when we flip things they change
1/2 is different from 2/1
but
if we have 1/(2^-2) and flip it to 2^-2/1 then *change the exponent*
so that we have 2^2/1
it turns out
that \[ \frac{1}{2^{-2}} = \frac{2^2}{1} \]

- phi

so we do two things: flip and *change the exponent*

- anonymous

ok

- anonymous

humm

- phi

now your problem is
\[ 4 \cdot \frac{1}{2^{-2}} \]
and 1/2^-2 is 2^2, so it is now
\[ 4 \cdot 2^2 \]

- phi

2^2 means 2*2
4* 2^2 means 4*2*2

- anonymous

ok nvm i got it u r just beating around the boosh sorry i figured it out thx thow

- phi

you should get 16

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