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anonymous

  • one year ago

so i got a math question for ya

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  1. anonymous
    • one year ago
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    wht is it

  2. anonymous
    • one year ago
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    I may be able to help. What is your question?

  3. anonymous
    • one year ago
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    In the equation x^2+3x-10=(x+g)(x+h) g and h are both intergers there are 2 possiable intergers for g wht are they

  4. anonymous
    • one year ago
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    b and a

  5. anonymous
    • one year ago
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    no g and h but only g im looking for

  6. anonymous
    • one year ago
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    oh

  7. welshfella
    • one year ago
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    first expand the RHS

  8. anonymous
    • one year ago
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    RHS?

  9. welshfella
    • one year ago
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    x^2+3x-10=(x+g)(x+h) x^2 + 3x - 10 = x^2 + gx + hx + gh

  10. welshfella
    • one year ago
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    right hand side

  11. welshfella
    • one year ago
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    x^2 + 3x - 10 = x^2 + gx + hx + gh x^2 + 3x - 10 = x^2 + (g + h)x + gh

  12. anonymous
    • one year ago
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    o ok

  13. welshfella
    • one year ago
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    now compare coefficients of x and x^0 g + h = 4 gh = -10

  14. welshfella
    • one year ago
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    now solve this system of equations to give you the values of g and h

  15. anonymous
    • one year ago
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    but i only need g

  16. welshfella
    • one year ago
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    oh sorry I don't know why i put 4 it should be 3 g + h = 3 gh = -10

  17. welshfella
    • one year ago
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    well find h in terms of g from first equation then plug it into the second

  18. welshfella
    • one year ago
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    from first equation h = 3 - g now sub in second g(3 - g) = -10 now solve this for g its a quadratic and you'll get 2 solutions

  19. anonymous
    • one year ago
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    thx

  20. anonymous
    • one year ago
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    nope

  21. anonymous
    • one year ago
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    nope

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spraguer (Moderator)
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