anonymous
  • anonymous
How would you get d= 7300 m^3 to m^2? An electrolytic tin-plating process gives a coating of 3.0 x10^-5 inches thick. How many square metres can be coated with 1kg of tin, d=7300 kg/m^3...is the full question, please just help me get the m^3 to m^2
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@paki @toxicsugar22 Can either of you help?
anonymous
  • anonymous
@sweetburger can you help?
anonymous
  • anonymous
@abb0t can you help?

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anonymous
  • anonymous
@aaronq
aaronq
  • aaronq
|dw:1441146852206:dw|
aaronq
  • aaronq
|dw:1441146891331:dw|
aaronq
  • aaronq
I meant 0.00003 inches for height, which is 7.62e-7 m (conversion done by google cuz i'm not 'murican). This is a volume, not a surface, but it has a fixed height. \(V=l*w*h=l*w*(7.62*10^{-7}~m)\) The volume of tin must be found with the mass and the density. \(\rho=\dfrac{m}{V}\rightarrow V=\dfrac{m}{\rho}=\dfrac{1~kg}{7300~kg/m^3}=0.0001369863013699~m~\approx0.000137~m^3\) \(V=l*w*(7.62*10^{-7}~m)= 0.000137~m^3\) Well make this a square base, so: \(x^2*(7.62*10^{-7}~m)= 0.000137~m^3\) Finally we solve for x and we get one of the sides of our coating.|dw:1441147497222:dw|
aaronq
  • aaronq
Actually solving for \(x^2\) gives you the area of the coating, so yeah you can stop there
anonymous
  • anonymous
will solving for x^3 give us a m^2 answer?
anonymous
  • anonymous
@aaronq ok, so looking at this, firstly thank you, but why are we finding volume, instead of let's say area? Is it because the coating has a thickness?
aaronq
  • aaronq
yes, the thickness indicates that the object has 3 dimensions and has a volume. Solving for \(\sf x^2\) gives you the area
aaronq
  • aaronq
The thickness indicates how large the material can coat the area. A thinner coating will give a larger area and viceversa.
anonymous
  • anonymous
Awesome Thanks, @aaronq I got 13.41m^2 Is this correct?!?
aaronq
  • aaronq
no problem! sorry, idk my calculator is elsewhere. just divide the volume by the height and that should be it
anonymous
  • anonymous
Ok... I did 1.37*10^-4 (volume) / 7.62*10^-7 (height) = 179.79m^4 Then finally took the square root of that and got 13.41m^2
anonymous
  • anonymous
But, i don't know if that is how the exponents on metres goes??? Sorry to keep asking things, just want to make sure i'm absolutely correct on units (my teacher is strict on units) @aaronq
aaronq
  • aaronq
the will cancel out and give you \(m^2\), remember i told you to follow the formula and divide the volume by the height? \(\sf \dfrac{volume}{height}=\dfrac{m^3}{m}=m^2\)
anonymous
  • anonymous
ok but then do you just leave the x^2???
aaronq
  • aaronq
So you have \(x^2*(7.62*10^{-7}~m)= 0.000137~m^3\) then just isolate \(x^2\)
anonymous
  • anonymous
because if you take the square root of 179.79 m^2 it comes out 13.41 m
anonymous
  • anonymous
so it would just be 179.79 m^2
aaronq
  • aaronq
they're asking you for square meters
aaronq
  • aaronq
yeah
anonymous
  • anonymous
Ok thanks!
aaronq
  • aaronq
ok cool, no problem

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