x3_drummerchick
  • x3_drummerchick
Please help me solve this! I'm stuck- will give medals!!
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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x3_drummerchick
  • x3_drummerchick
|dw:1441131240410:dw|
anonymous
  • anonymous
so whats the question?
x3_drummerchick
  • x3_drummerchick
solve for real solutions

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anonymous
  • anonymous
it seems to be already solved, copy paste the whole question.
x3_drummerchick
  • x3_drummerchick
its not solved, i have to solve for x
anonymous
  • anonymous
are we just trying to find x? what grade math is this?
anonymous
  • anonymous
ok, if we trying to find x it is simple
anonymous
  • anonymous
cross multiply to get rid of complex fractions then get rid of denominator by multiplication. should be straight forward from there
x3_drummerchick
  • x3_drummerchick
\[\frac{ x+\frac{ 8 }{ x } }{ 6+\frac{ 2 }{ x } }=3x\]
x3_drummerchick
  • x3_drummerchick
ill show you what all i did first, im stuck on the last half
x3_drummerchick
  • x3_drummerchick
|dw:1441131497407:dw|
x3_drummerchick
  • x3_drummerchick
|dw:1441131523486:dw|
anonymous
  • anonymous
\[x^2+8=18x^2+6x\]
anonymous
  • anonymous
move everything to one side and solve the quadratic
x3_drummerchick
  • x3_drummerchick
wait howd you get that?
x3_drummerchick
  • x3_drummerchick
i got that far, then i put it in the quad formula, but the answer keeps comnig out wrong
anonymous
  • anonymous
?
anonymous
  • anonymous
what do you mean the answer keeps coming out wrong?
x3_drummerchick
  • x3_drummerchick
i keep getting \[\frac{ -3+2\sqrt{145} }{ 17 }\]
x3_drummerchick
  • x3_drummerchick
its supposed to be that answer, but without the 2.
anonymous
  • anonymous
okay, just a sec...\[x=\frac{ -6 \pm \sqrt{\left( -6 \right)^2-4\left( 17 \right) \left(-8 \right)} }{ 2\left( 17 \right) }\]right so far?
x3_drummerchick
  • x3_drummerchick
yes
anonymous
  • anonymous
\[x=\frac{ \left( -6 \right)\pm \sqrt{36+544} }{ 2\left( 17 \right) }=\frac{ \left( -6 \right)\pm \sqrt{580} }{ 2\left( 17 \right) }=\frac{ \left( -6 \right)\pm \sqrt{4\cdot145} }{ 2\left( 17 \right) }\]
x3_drummerchick
  • x3_drummerchick
anonymous
  • anonymous
\[=\frac{ \cancel{2}\cdot\left( -3 \right)\pm \cancel{2}\cdot \sqrt{145} }{ \cancel{2}\left( 17 \right) }=\frac{ \left( -3 \right)\pm \sqrt{145} }{ \left( 17 \right) }\]
x3_drummerchick
  • x3_drummerchick
oh wait. i see what i did there.. i forgot to take the square root of the 4, i wrote 4 instead of 2. so when i simplified i was still left with the 2 in the numerator
x3_drummerchick
  • x3_drummerchick
good call, my friend. youre pretty good at this! :)
anonymous
  • anonymous
factor out a 2 from the numerator and denominator:\[=\frac{ 2\cdot\left( -3 \right)\pm 2\cdot \sqrt{145} }{ 2\left( 17 \right) }=\frac{ 2\cdot\left( \left( -3 \right)\pm \sqrt{145} \right) }{ 2\cdot\left( 17 \right) }\]
anonymous
  • anonymous
good job!!!
x3_drummerchick
  • x3_drummerchick
i got the harder stuff down, i just suck at basic math lol thanks again!
anonymous
  • anonymous
don't say that! you'll start to believe it!

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