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x3_drummerchick

  • one year ago

Please help me solve this! I'm stuck- will give medals!!

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  1. x3_drummerchick
    • one year ago
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    |dw:1441131240410:dw|

  2. anonymous
    • one year ago
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    so whats the question?

  3. x3_drummerchick
    • one year ago
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    solve for real solutions

  4. anonymous
    • one year ago
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    it seems to be already solved, copy paste the whole question.

  5. x3_drummerchick
    • one year ago
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    its not solved, i have to solve for x

  6. anonymous
    • one year ago
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    are we just trying to find x? what grade math is this?

  7. anonymous
    • one year ago
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    ok, if we trying to find x it is simple

  8. anonymous
    • one year ago
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    cross multiply to get rid of complex fractions then get rid of denominator by multiplication. should be straight forward from there

  9. x3_drummerchick
    • one year ago
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    \[\frac{ x+\frac{ 8 }{ x } }{ 6+\frac{ 2 }{ x } }=3x\]

  10. x3_drummerchick
    • one year ago
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    ill show you what all i did first, im stuck on the last half

  11. x3_drummerchick
    • one year ago
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    |dw:1441131497407:dw|

  12. x3_drummerchick
    • one year ago
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    |dw:1441131523486:dw|

  13. anonymous
    • one year ago
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    \[x^2+8=18x^2+6x\]

  14. anonymous
    • one year ago
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    move everything to one side and solve the quadratic

  15. x3_drummerchick
    • one year ago
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    wait howd you get that?

  16. x3_drummerchick
    • one year ago
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    i got that far, then i put it in the quad formula, but the answer keeps comnig out wrong

  17. anonymous
    • one year ago
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    ?

  18. anonymous
    • one year ago
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    what do you mean the answer keeps coming out wrong?

  19. x3_drummerchick
    • one year ago
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    i keep getting \[\frac{ -3+2\sqrt{145} }{ 17 }\]

  20. x3_drummerchick
    • one year ago
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    its supposed to be that answer, but without the 2.

  21. anonymous
    • one year ago
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    okay, just a sec...\[x=\frac{ -6 \pm \sqrt{\left( -6 \right)^2-4\left( 17 \right) \left(-8 \right)} }{ 2\left( 17 \right) }\]right so far?

  22. x3_drummerchick
    • one year ago
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    yes

  23. anonymous
    • one year ago
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    \[x=\frac{ \left( -6 \right)\pm \sqrt{36+544} }{ 2\left( 17 \right) }=\frac{ \left( -6 \right)\pm \sqrt{580} }{ 2\left( 17 \right) }=\frac{ \left( -6 \right)\pm \sqrt{4\cdot145} }{ 2\left( 17 \right) }\]

  24. x3_drummerchick
    • one year ago
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  25. anonymous
    • one year ago
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    \[=\frac{ \cancel{2}\cdot\left( -3 \right)\pm \cancel{2}\cdot \sqrt{145} }{ \cancel{2}\left( 17 \right) }=\frac{ \left( -3 \right)\pm \sqrt{145} }{ \left( 17 \right) }\]

  26. x3_drummerchick
    • one year ago
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    oh wait. i see what i did there.. i forgot to take the square root of the 4, i wrote 4 instead of 2. so when i simplified i was still left with the 2 in the numerator

  27. x3_drummerchick
    • one year ago
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    good call, my friend. youre pretty good at this! :)

  28. anonymous
    • one year ago
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    factor out a 2 from the numerator and denominator:\[=\frac{ 2\cdot\left( -3 \right)\pm 2\cdot \sqrt{145} }{ 2\left( 17 \right) }=\frac{ 2\cdot\left( \left( -3 \right)\pm \sqrt{145} \right) }{ 2\cdot\left( 17 \right) }\]

  29. anonymous
    • one year ago
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    good job!!!

  30. x3_drummerchick
    • one year ago
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    i got the harder stuff down, i just suck at basic math lol thanks again!

  31. anonymous
    • one year ago
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    don't say that! you'll start to believe it!

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