1. anonymous

|dw:1441131240410:dw|

2. anonymous

so whats the question?

3. anonymous

solve for real solutions

4. anonymous

it seems to be already solved, copy paste the whole question.

5. anonymous

its not solved, i have to solve for x

6. anonymous

are we just trying to find x? what grade math is this?

7. anonymous

ok, if we trying to find x it is simple

8. anonymous

cross multiply to get rid of complex fractions then get rid of denominator by multiplication. should be straight forward from there

9. anonymous

$\frac{ x+\frac{ 8 }{ x } }{ 6+\frac{ 2 }{ x } }=3x$

10. anonymous

ill show you what all i did first, im stuck on the last half

11. anonymous

|dw:1441131497407:dw|

12. anonymous

|dw:1441131523486:dw|

13. anonymous

$x^2+8=18x^2+6x$

14. anonymous

move everything to one side and solve the quadratic

15. anonymous

wait howd you get that?

16. anonymous

i got that far, then i put it in the quad formula, but the answer keeps comnig out wrong

17. anonymous

?

18. anonymous

what do you mean the answer keeps coming out wrong?

19. anonymous

i keep getting $\frac{ -3+2\sqrt{145} }{ 17 }$

20. anonymous

its supposed to be that answer, but without the 2.

21. anonymous

okay, just a sec...$x=\frac{ -6 \pm \sqrt{\left( -6 \right)^2-4\left( 17 \right) \left(-8 \right)} }{ 2\left( 17 \right) }$right so far?

22. anonymous

yes

23. anonymous

$x=\frac{ \left( -6 \right)\pm \sqrt{36+544} }{ 2\left( 17 \right) }=\frac{ \left( -6 \right)\pm \sqrt{580} }{ 2\left( 17 \right) }=\frac{ \left( -6 \right)\pm \sqrt{4\cdot145} }{ 2\left( 17 \right) }$

24. anonymous

25. anonymous

$=\frac{ \cancel{2}\cdot\left( -3 \right)\pm \cancel{2}\cdot \sqrt{145} }{ \cancel{2}\left( 17 \right) }=\frac{ \left( -3 \right)\pm \sqrt{145} }{ \left( 17 \right) }$

26. anonymous

oh wait. i see what i did there.. i forgot to take the square root of the 4, i wrote 4 instead of 2. so when i simplified i was still left with the 2 in the numerator

27. anonymous

good call, my friend. youre pretty good at this! :)

28. anonymous

factor out a 2 from the numerator and denominator:$=\frac{ 2\cdot\left( -3 \right)\pm 2\cdot \sqrt{145} }{ 2\left( 17 \right) }=\frac{ 2\cdot\left( \left( -3 \right)\pm \sqrt{145} \right) }{ 2\cdot\left( 17 \right) }$

29. anonymous

good job!!!

30. anonymous

i got the harder stuff down, i just suck at basic math lol thanks again!

31. anonymous

don't say that! you'll start to believe it!