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anonymous

  • one year ago

Ellen wants to purchase a book that is regularly priced at $18. The book is discounted 15%. She also needs to pay a 6% sales tax on the discounted price. What is the total amount Ellen will pay for the book? Enter your answer in the box.

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  1. anonymous
    • one year ago
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    @Michele_Laino

  2. anonymous
    • one year ago
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    @Loser66

  3. itsbribro
    • one year ago
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    $16.22 i believe

  4. anonymous
    • one year ago
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    ok :)

  5. Michele_Laino
    • one year ago
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    after discount, the new price is: \[\Large 18 - \left( {\frac{{15}}{{100}} \cdot 18} \right) = ...?\]

  6. itsbribro
    • one year ago
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    oops i messed up lol

  7. anonymous
    • one year ago
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    153/10

  8. anonymous
    • one year ago
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    @Michele_Laino

  9. anonymous
    • one year ago
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    is it 15.3 @Michele_Laino

  10. Michele_Laino
    • one year ago
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    please wait, I check your result

  11. anonymous
    • one year ago
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    ok :)

  12. Michele_Laino
    • one year ago
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    yes! correct!

  13. anonymous
    • one year ago
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    ok :)

  14. anonymous
    • one year ago
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  15. Michele_Laino
    • one year ago
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    now, the requested price is given by the subsequent computation: \[\Large 15.3 + \left( {\frac{6}{{100}} \cdot 15.3} \right) = ...?\]

  16. anonymous
    • one year ago
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    15.6

  17. Michele_Laino
    • one year ago
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    I got a different result

  18. anonymous
    • one year ago
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    what did you get?

  19. Michele_Laino
    • one year ago
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    hint: \[\Large \frac{6}{{100}} \cdot 15.3 = ...?\]

  20. anonymous
    • one year ago
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    0.918 @Michele_Laino

  21. Michele_Laino
    • one year ago
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    and 15.3+0.918=...?

  22. anonymous
    • one year ago
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    16.128

  23. anonymous
    • one year ago
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    i mean 16.218

  24. Michele_Laino
    • one year ago
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    yes! correct! That result can be rounded off to 16.22

  25. anonymous
    • one year ago
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    so whats the final answer?

  26. Michele_Laino
    • one year ago
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    the final answer is 16.22

  27. anonymous
    • one year ago
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    are you sure?

  28. Michele_Laino
    • one year ago
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    yes!

  29. anonymous
    • one year ago
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    ok :)

  30. anonymous
    • one year ago
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  31. Michele_Laino
    • one year ago
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    here the rate of the car is: space/time, \[\Large \frac{{1/6}}{{3/5}} = \frac{1}{6} \cdot \frac{5}{3} = ...?\]

  32. Michele_Laino
    • one year ago
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    please express your result as a fraction

  33. anonymous
    • one year ago
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    1/10

  34. Michele_Laino
    • one year ago
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    I'm sorry, it is wrong

  35. anonymous
    • one year ago
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    1/10 is wrong?

  36. Michele_Laino
    • one year ago
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    yes!

  37. anonymous
    • one year ago
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    5/18?

  38. Michele_Laino
    • one year ago
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    correct!

  39. Michele_Laino
    • one year ago
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    that rate is the space traveled in 1 hour

  40. Michele_Laino
    • one year ago
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    so the requested distance is: distance= speed*time \[\Large {\text{distance}} = \frac{5}{{18}} \cdot 1 = ...?\]

  41. anonymous
    • one year ago
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    sorry i meant 5/18

  42. Michele_Laino
    • one year ago
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    correct!

  43. anonymous
    • one year ago
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    is that the final answer?

  44. Michele_Laino
    • one year ago
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    yes!

  45. anonymous
    • one year ago
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    okay :)

  46. Michele_Laino
    • one year ago
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    :)

  47. anonymous
    • one year ago
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    @Michele_Laino

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  48. Michele_Laino
    • one year ago
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    part A) If I call with p the price in September, then I can write this equation: \[\Large \begin{gathered} p + \left( {\frac{{20}}{{100}} \cdot p} \right) = 1.5 \hfill \\ \hfill \\ or: \\ \\ 1.2p = 1.5 \hfill \\ \end{gathered} \] please solve for p

  49. anonymous
    • one year ago
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    p=1.25

  50. Michele_Laino
    • one year ago
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    correct!

  51. anonymous
    • one year ago
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    is that the final answer for part A?

  52. Michele_Laino
    • one year ago
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    yes!

  53. anonymous
    • one year ago
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    ok now part b?

  54. Michele_Laino
    • one year ago
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    here, we note that: in september the earned money is: \[\Large 900 \cdot \left( {1.25 \cdot \frac{{40}}{{100}}} \right) = ...?\] whereas in october, the earned money is: \[\Large 700 \cdot \left( {1.5 \cdot \frac{{40}}{{100}}} \right) = ...?\] please compute both amounts of money

  55. anonymous
    • one year ago
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    i got 450 for september and 420 for october

  56. Michele_Laino
    • one year ago
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    correct! So, what is your answer?

  57. anonymous
    • one year ago
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    um its says choose one... for the first one these are the multiple choices.. september or october and the other choose one are... $30, $75, or $190

  58. Michele_Laino
    • one year ago
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    yes! 450-420=...?

  59. anonymous
    • one year ago
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    30

  60. Michele_Laino
    • one year ago
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    so what are your options?

  61. anonymous
    • one year ago
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    for which one... there are two answers for part b

  62. Michele_Laino
    • one year ago
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    yes! for part B) there are 2 options

  63. anonymous
    • one year ago
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    right

  64. Michele_Laino
    • one year ago
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    first option: is september or october?

  65. anonymous
    • one year ago
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    yes

  66. Michele_Laino
    • one year ago
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    please choose

  67. anonymous
    • one year ago
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    september

  68. Michele_Laino
    • one year ago
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    correct! second option: is 30, 75 or 190?

  69. anonymous
    • one year ago
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    yea

  70. anonymous
    • one year ago
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    $30?

  71. Michele_Laino
    • one year ago
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    correct!

  72. anonymous
    • one year ago
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    yay! so september and 30

  73. Michele_Laino
    • one year ago
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    yes!

  74. anonymous
    • one year ago
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    @Michele_Laino

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  75. Michele_Laino
    • one year ago
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    part A) hint: your line passes at point (0,0), namely the origin

  76. anonymous
    • one year ago
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    i got... a,c and e

  77. Michele_Laino
    • one year ago
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    correct!

  78. anonymous
    • one year ago
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    yay! thanks so much! :)

  79. Michele_Laino
    • one year ago
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    :)

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