So, I need some help with Logarithms. The equation is: log (subscript 3) x^2 + log (subscript 3) 9 = 4.
I thought you multiply (x^2)(9) in order to get one log on the left side, so you're left with...
log (subscript 3) 9x^2=4 and because the log is the exponent, you have log (subscript 3) 9x^2=3^4=81, which makes x=3, but that is the wrong answer. Thank You!

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\[\log_3(x^2)+\log_3(9)=4 \\ \text{ yes you can use product rule } \\ \log_3(9x^2)=4\]

you can then write in the equivalent exponential form

\[\log_b(x)=y \implies b^y=x\]

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