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anonymous
 one year ago
The equation tan(x+pi/6) is equal to _____.
a. √3 tanx+1/√3tanx
b. tanx+√3/1√3 tanx
c. tanx√3/1+√3tanx
d. √3 tanx1/√3+tanx
anonymous
 one year ago
The equation tan(x+pi/6) is equal to _____. a. √3 tanx+1/√3tanx b. tanx+√3/1√3 tanx c. tanx√3/1+√3tanx d. √3 tanx1/√3+tanx

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freckles
 one year ago
Best ResponseYou've already chosen the best response.1try using the sum formula identity for tan

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(a+b)=\frac{\tan(a)+\tan(b)}{1\tan(a)\tan(b)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got (tan(x)+tan(pi/6))/1tan(x)tan(pi/6) how does that help me?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1do you know how to evaluate tan(pi/6)?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(\frac{\pi}{6})=\frac{\sin(\frac{\pi}{6})}{\cos(\frac{\pi}{6})}=....\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but the equation is tan(x+pi/6) so how does that work

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so when you used the sum identity just a sec ago you don't see tan(pi/6)?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1I'm asking you to evaluate tan(pi/6)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(x+\frac{\pi}{6})=\frac{\tan(x)+\color{red}{\tan(\frac{\pi}{6})}}{1\tan(x) \color{red}{\tan(\frac{\pi}{6})}}\] I'm asking you to evaluate this thing in red

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i did that now what

freckles
 one year ago
Best ResponseYou've already chosen the best response.1what did you get for the thing in red?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1the unit circle says tan(pi/6) is..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(so i got tan(x)+rt(3))/(1tan(x)rt(3))

freckles
 one year ago
Best ResponseYou've already chosen the best response.1hmm shouldn't tan(pi/6) be 1/sqrt(3)?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(\frac{\pi}{6})=\frac{\sin(\frac{\pi}{6})}{\cos(\frac{\pi}{6})}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}=\frac{1}{\sqrt{3}}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(x+\frac{\pi}{6})=\frac{\tan(x)+\color{red}{\frac{1}{\sqrt{3}}}}{1\tan(x) \color{red}{\frac{1}{\sqrt{3}}}}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1multiply top and bottom of the big fraction by sqrt(3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so how do i get rid of the extra fractions

freckles
 one year ago
Best ResponseYou've already chosen the best response.1multiply top and bottom of the big fraction by sqrt(3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so (rt(3)tan(x))/(rt(3)tanx)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1you left a term out on top

freckles
 one year ago
Best ResponseYou've already chosen the best response.1sqrt(3)/sqrt(3) isn't 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thx a ton for all the help!!!

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(x+\frac{\pi}{6})=\frac{\tan(x)+\color{red}{\frac{1}{\sqrt{3}}}}{1\tan(x) \color{red}{\frac{1}{\sqrt{3}}}} \cdot \frac{\color{blue}{\sqrt{3}}}{ \color{blue}{\sqrt{3}}} \\ \tan(x+\frac{\pi}{6})= \frac{\color{blue}{\sqrt{3}} \tan(x)+\frac{\color{blue }{\sqrt{3}}}{\color{red}{\sqrt{3}}}}{\color{blue}{\sqrt{3}}\tan(x) \frac{\color{blue}{\sqrt{3}}}{\color{red}{\sqrt{3}}}} \]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1and yes you get a as a result
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