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anonymous

  • one year ago

Calculate a chain of 4x4 matrices (don’t multiply them together) that will rotate points about the vector A = [(.5)^1/2, 1.73, (.5)^1/2]. Show your work. Helpful trig evaluations: tan (60 deg) = 1.73; tan (45 deg) = 1.0

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  1. phi
    • one year ago
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    I know it's possible, but I don't remember the details. How much do you know ?

  2. phi
    • one year ago
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    This gives an algorithm http://inside.mines.edu/fs_home/gmurray/ArbitraryAxisRotation/ it looks messy

  3. anonymous
    • one year ago
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  4. anonymous
    • one year ago
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    have a look

  5. phi
    • one year ago
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    your vector A in spherical coords means phi = 45 and theta= 60 |dw:1441136301303:dw|

  6. phi
    • one year ago
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    according to the link, the steps are 1 rotate 60º so the vector is in the xz plane 2 then rotate that by 45 so it points in the z direction 3 now do the rotation you want 4,5 then undo step 2 and then step 1

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