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anonymous

  • one year ago

Look at the figure: An image of a right triangle is shown with an angle labeled x. If tan x° = 11 divided by r and cos x° = r divided by s, what is the value of sin x°? sin x° = s divided by 11 sin x° = 11 divided by s sin x° = 11r sin x° = 11s

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  1. anonymous
    • one year ago
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    @dan815 @campbell_st

  2. anonymous
    • one year ago
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  3. campbell_st
    • one year ago
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    so knowing the about tan(x): 11 is the opposite side and r is the adjacent side cos(x) r is the adjacent side and s is the hypotenuse so that means sin(x) = 11/s opposite/hypotenuse

  4. anonymous
    • one year ago
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    wait thats it ?

  5. anonymous
    • one year ago
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    wow this is easier than i thought

  6. campbell_st
    • one year ago
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    that's it you need to know tan = opposite/adjacent, cos = adjacent/hypotenuse and sin = opposite/hypotenuse

  7. anonymous
    • one year ago
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    ok thanks :)

  8. campbell_st
    • one year ago
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    so by knowing the ratio basics you can label the sides

  9. dinamix
    • one year ago
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    sinx = 11 divided by s this the answer cuz sinx = 11 /s

  10. dinamix
    • one year ago
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    @please_help_me

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