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anonymous
 one year ago
In 2010 a company installed a new machine in one of its factories at a cost of $680,000. The
machine is linearly depreciated over 30 years with a scrap value of $80,000.
4. Find an expression for the machine value in the t th year of use (0 < t < 30).
anonymous
 one year ago
In 2010 a company installed a new machine in one of its factories at a cost of $680,000. The machine is linearly depreciated over 30 years with a scrap value of $80,000. 4. Find an expression for the machine value in the t th year of use (0 < t < 30).

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.1sorry, it is scrap value...

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1linearly depreciated means it is a line with constant slope, y = m*x+b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 20000 so m ans is v(t) = 20,000t + 680000?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1the slope will be how much it has gone down in over that 30 years time... m = (680,000  80,000) / 30

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1looks good, the y intercept is the starting value when time t=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my answer is right? the second part is: Find the machine’s value in the year 2024. how do I calculate that?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1yes correct, they installed the achine in 2010, so 20242010 = 14 years of depreciation, let t=14 years
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