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anonymous
 one year ago
(csc(6x)+cot(6x))/(csc(6x)cot(6x))=____
(Cot^2)(3x)
cot(3x)
(cot^2)(6x)
tan(6x)
anonymous
 one year ago
(csc(6x)+cot(6x))/(csc(6x)cot(6x))=____ (Cot^2)(3x) cot(3x) (cot^2)(6x) tan(6x)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got it to (1/sin(6x)+1/tan(6x))/(1/sin(6x)1/tan(6x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.0hmm... let's try multiplying the top and bottom of the the original expression by the conjugate of the bottom

freckles
 one year ago
Best ResponseYou've already chosen the best response.0I'm thinking about using the identity \[1+\cot^2(\theta)=\csc^2(\theta)\] maybe

freckles
 one year ago
Best ResponseYou've already chosen the best response.0though this might just be easier to plug in 20 deg into the first expression and see which one below when pluggin 20 degs gives the same result
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