## anonymous one year ago (csc(6x)+cot(6x))/(csc(6x)-cot(6x))=____ (Cot^2)(3x) cot(3x) (cot^2)(6x) tan(6x)

1. anonymous

i got it to (1/sin(6x)+1/tan(6x))/(1/sin(6x)-1/tan(6x)

2. freckles

hmm... let's try multiplying the top and bottom of the the original expression by the conjugate of the bottom

3. freckles

I'm thinking about using the identity $1+\cot^2(\theta)=\csc^2(\theta)$ maybe

4. freckles

though this might just be easier to plug in 20 deg into the first expression and see which one below when pluggin 20 degs gives the same result