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anonymous
 one year ago
Solve x3 = 64 over 27.
±8 over 3
8 over 3
±4 over 3
4 over 3
anonymous
 one year ago
Solve x3 = 64 over 27. ±8 over 3 8 over 3 ±4 over 3 4 over 3

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2take cube root both sides to cancel out the cube

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2here is an example \[\huge\rm \sqrt[3]{m^3} = \sqrt[3]{27}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2you can convert root to exponent cube root of m^3 is same as \[\huge\rm m^{3 \times \frac{ 1 }{ 3 }}\] then you can cancel out the 3's \[\huge\rm m^{\cancel{3} \times \frac{ 1 }{ \cancel{3 }}}=m\] that's how you can take cube root both sides to cancel out cube

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2take cube root both sides !

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \sqrt[3]{x^3}=\sqrt[3]{\frac{ 64 }{ 27 }}\] that's how we should take cube root cube= 3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \sqrt[3]{\frac{ a }{ b }}=\frac{ \sqrt[3]{a} }{ \sqrt[3]{b} }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2take cube root of the numerator and take cube root of the denominator !
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