## anonymous one year ago Solve x3 = 64 over 27. ±8 over 3 8 over 3 ±4 over 3 4 over 3

1. anonymous

@dan815 @Nnesha

2. Nnesha

take cube root both sides to cancel out the cube

3. anonymous

how

4. Nnesha

here is an example $\huge\rm \sqrt[3]{m^3} = \sqrt[3]{27}$

5. anonymous

O.o

6. anonymous

im confuzzled

7. Nnesha

you can convert root to exponent cube root of m^3 is same as $\huge\rm m^{3 \times \frac{ 1 }{ 3 }}$ then you can cancel out the 3's $\huge\rm m^{\cancel{3} \times \frac{ 1 }{ \cancel{3 }}}=m$ that's how you can take cube root both sides to cancel out cube

8. Nnesha

take cube root both sides !

9. anonymous

*cries*

10. anonymous

idk how

11. Nnesha

$\huge\rm \sqrt[3]{x^3}=\sqrt[3]{\frac{ 64 }{ 27 }}$ that's how we should take cube root cube= 3

12. Nnesha

$\huge\rm \sqrt[3]{\frac{ a }{ b }}=\frac{ \sqrt[3]{a} }{ \sqrt[3]{b} }$

13. Nnesha

take cube root of the numerator and take cube root of the denominator !