What did I do wrong in this problem!? Help! ill give medals

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What did I do wrong in this problem!? Help! ill give medals

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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drummer chicks unite!!! :D
sorry, that was random

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Other answers:

woah!
well what's the problem list the equation so we can help you
i took a picture of all my work- its i the attachment above ^
i know u guys are here do something already
looking backwards it seems like you have in that thinking that -4(2) = -24
The quadradic formula? is that what your doing
this is the problem: \[\frac{ x + \frac{ 5 }{ x } }{ 1+\frac{ 6 }{ x } }=4x\]
\[\frac{-24 \pm 2 \sqrt{159}}{6}= \frac{\frac{-24}{2} \pm \frac{2 \sqrt{159}}{2}}{\frac{6}{2}} \\ \\ =\frac{-12 \pm \sqrt{159}}{3}\]
Try mathway
other than that your work looks great just end part needs fixing
im confused :(
in the end when you divided -24 by 2 you wrote -4 this is not true
why cant i simplify the numerator and denominator like afraction?
\[\frac{-24 \pm 2 \sqrt{159}}{6} \\ \text{ you can separate the fraction } \\ \\ \frac{-24}{6} \pm \frac{2 \sqrt{159}}{6} \\ -4 \pm \frac{\sqrt{159}}{3}\]
maybe that is what you meant to do
Look at your last step, the solution. Now look one step up.
-24 and 6 simplify to -12 and 3, not -4 and 3
ahhh there we go, that makes more sense to me
You made a small mistake in the very last step.
i did this same thing last time lol thanks!!
\(\dfrac{-24 \pm 2\sqrt{159} }{6} = \dfrac{\cancel 2 (-12 \pm \sqrt{159})}{\cancel 2(3)}\)
just curious so this didn't make any sense: \[\frac{-24 \pm 2 \sqrt{159}}{6}= \frac{\frac{-24}{2} \pm \frac{2 \sqrt{159}}{2}}{\frac{6}{2}} \\ \\ =\frac{-12 \pm \sqrt{159}}{3}\] ?
@freckles You figured it out way back.
i kinda understand that way that you wrote, the other way was easier lol
ok well as long as you get it

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