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anonymous

  • one year ago

Graph the following inequalities on the same grid and shade the solution region that is common to all of the inequalities. a. y => 6 - 2/3x b. y <= 4 + x c. y <= 11 - 8(x - 7)

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  1. anonymous
    • one year ago
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    @nincompoop

  2. anonymous
    • one year ago
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    Please help @nincompoop

  3. DanJS
    • one year ago
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    Which do you need help with, graphing the three lines, or shading the thing?

  4. anonymous
    • one year ago
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    YOU HAVE TO GRAPH FIRST, THEN SHADE

  5. DanJS
    • one year ago
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    right, which do you need help with?

  6. anonymous
    • one year ago
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    Um solving them.. Idk how to do it really

  7. anonymous
    • one year ago
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    But just wait like ten or so minutes. I will brb

  8. DanJS
    • one year ago
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    For each line, you need two points to graph them pick a small x value and calculate what y is for 2 values of x graph all three lines that way

  9. DanJS
    • one year ago
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    the line is dotted if it not inclued, greater than or less than the line is solid if it is included, greater than or equal to, or less than or equal to

  10. DanJS
    • one year ago
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    if greater, shade above, if less shade below the line the solution set is the overlapping region of all three lines

  11. DanJS
    • one year ago
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    here is a small short video series to learn it... i have to run... goodluck https://www.khanacademy.org/math/algebra-basics/core-algebra-graphing-lines-slope/core-algebra-graphing-linear-inequalities/v/graphing-inequalities-2

  12. DanJS
    • one year ago
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    here is the solution to check after you figure it out... it is the overlapping of all three lines region

  13. DanJS
    • one year ago
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    https://www.desmos.com/calculator

  14. anonymous
    • one year ago
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    |dw:1441146727594:dw|

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