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anonymous
 one year ago
Fan and medal , HELP PLEASEEE
A satellite is in circular orbit 25,000 miles above Earth.
Write an equation for the orbit of this satellite if the origin is at the center of the Earth.
Use 8,000 as the diameter of the Earth. ??
anonymous
 one year ago
Fan and medal , HELP PLEASEEE A satellite is in circular orbit 25,000 miles above Earth. Write an equation for the orbit of this satellite if the origin is at the center of the Earth. Use 8,000 as the diameter of the Earth. ??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so this is the equ of a circle which is : (xa)^2+(yb)^2=R^2 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Leyla ente 3arabiye? :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so let us get the coordinate of the center and as it says that the center of the satellite is of the earth soo...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then the center which is taken as origin has coordinates O(0,0) so now we can write the equ. As x^2y^2=R^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Understood till now??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but im still confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok and the satellite is 25000 miles over the earth and the earth has a diameter of 8000 miles thus a radius of 4000miles therefore from the center pf the earth to the satellite which is the radius of the equation is 25000+4000=29000 therefore the equ. Gives us x^2+y^2=25000^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Whats confusing you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand now , I thought that , I need more process than that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know more formulas etc , but thank you so much !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your welcome :) btw are you arab?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not I'm not lol, why ?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0If you need to find the amount of time the satellite takes to complete one orbit, this page should help you. http://www.1728.org/kepler3a.htm 1.1613 days by the way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hehe nothing forget it :p

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0That page has the formula you will need time = sq root[(4*PI^2 * radius^3) / (G*m)] If you need some help with that, I'll help you

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well I dont need the time, but thank you anyway, BUT i need help with a different question you think that you can help? @wolf1728

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0Well, ask the question and let's see.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Center at (2, 4), tangent to xaxis

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0Is that for a circle?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0Okay, if the circle is tangent to the xaxis and center is at x=2 y =4 then it would need a radius of 4.

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0Circle's equation formula is: (x a)² + (y b)² = r² where center = (a, b)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 2 is a, and 4 is b ?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0yes and r^2 would be 16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank youuuuuuuuu so much , I feel like i love u right now lol jk , but thank seriusly :)

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.0ok you are welcome :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0heeyy hold on! , i dont want to bother you but i have a question, Center in the first quadrant: tangent to x=5 the xaxis and the yaxis. So this question is kinda the same like the previus ?
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