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lisa123

  • one year ago

Slyanite is a mineral that contains 28.0% gold by mass. How much sylvanite would you need to dig up to obtain 83.0g of gold

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  1. lisa123
    • one year ago
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    @phi

  2. Vocaloid
    • one year ago
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    set up a proportion mass of gold/total mass = 28/100 that gives us 83.0/x = 28/100 solve for x

  3. anonymous
    • one year ago
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    Wouldn't it be 0.28 times 83?

  4. Vocaloid
    • one year ago
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    not quite. if we wanted to know how much gold was in 83.0 grams of slyaniate, then yes, your approach would work, but the question wants to know how much sylvaniate has 83.0 g of gold

  5. lisa123
    • one year ago
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    okay thank you @vocaloid I got the answer right!

  6. phi
    • one year ago
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    ***Wouldn't it be 0.28 times 83? *** no, it would be 0.28 * unknown amount of mineral = 83 g pure gold or 0.28 x= 83 solve for x this will give the same answer as using proportions / ratios

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