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mathmath333

  • one year ago

In how many ways can 5 prizes can be distributed to 8 students if each student can get any number of prizes ?

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{ In how many ways can 5 prizes can be distributed to 8 students}\hspace{.33em}\\~\\ & \normalsize \text{ if each student can get any number of prizes ?}\hspace{.33em}\\~\\ & a)\ 40 \hspace{.33em}\\~\\ & b)\ 5^{8} \hspace{.33em}\\~\\ & c)\ 8^{5} \hspace{.33em}\\~\\ & d)\ 120 \hspace{.33em}\\~\\ \end{align}}\)

  2. anonymous
    • one year ago
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    I can help.

  3. anonymous
    • one year ago
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    Lets see... 5/8, correct?

  4. mathmath333
    • one year ago
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    it is \(5^{8}\) not 5/8

  5. anonymous
    • one year ago
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    Five to the eighth power? Okay. So your answer is B.

  6. mathmath333
    • one year ago
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    lol i dont know answer , i m asking for it

  7. anonymous
    • one year ago
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    Your answer is B. : )

  8. phi
    • one year ago
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    the first prize can go to any of 8 people the 2nd prize can go to any of 8 people etc, .... how about 8^5 ?

  9. anonymous
    • one year ago
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    but @phi what if the first had five prizes at time xD or so hmmm

  10. dan815
    • one year ago
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    |dw:1441150449776:dw|

  11. wolf1728
    • one year ago
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    There are 8 ways that all 5 prizes can be given to 1 person Now for giving 4 prizes to 1 person and 1 prize to 1 person Would that be 8*7 ways or 56?

  12. dan815
    • one year ago
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    distinguishable prizes eh

  13. phi
    • one year ago
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    I am assuming distinguishable prizes.

  14. mathmath333
    • one year ago
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    what is default if it is not given (identical or distinct)

  15. dan815
    • one year ago
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    if its identical its a stars and bars question, visualize like that drawing

  16. dan815
    • one year ago
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    okay there is 1 way to do the non identical case its not that pretty

  17. dan815
    • one year ago
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    oh wait its not even choose since the presents are not identical its 8 P

  18. dan815
    • one year ago
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    ________ 5 presents, in 8 different spots = 8 ways presents 4,1 in 2 spots, = 8 p 2 * 5 choose 4 presents 3,2 , 8 p 2 * 5 chose 3 * 4 choose 2 3,1,1, 8 p 3 * 5 choose 3* 4 choose 1 * 3 choose 1 2,2,1 ... complete these 2,1,1,1 1,1,1,1,1 add em all up

  19. dan815
    • one year ago
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    ill think about some neater way

  20. dan815
    • one year ago
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    later xD

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