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clara1223

  • one year ago

find the limit at x approaches -5 of (30-6x)/(x+5) a) 12 b) 6 c) does not exist d) 0 e) -6/5

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  1. clara1223
    • one year ago
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    I already took a 6 out of the numerator so i have 6(-x+5)/(x+5)

  2. LynFran
    • one year ago
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    \[\lim_{x \rightarrow -5}\frac{ (30-6x) }{ (x+5) }\]\[\lim_{x \rightarrow -5}\frac{ 6(5-x) }{ (x+5) }\]\[\lim_{x \rightarrow -5}\frac{ 6(5-(-5)) }{ (-5+5) }\]

  3. LynFran
    • one year ago
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    u would get zero in the denominator so the limit DNE

  4. clara1223
    • one year ago
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    But then you have a 0 in the denominator. So does the limit not exist?

  5. clara1223
    • one year ago
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    Oh, thank you

  6. anonymous
    • one year ago
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    Why isnt infinity included in your choices?

  7. LynFran
    • one year ago
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    welcome

  8. clara1223
    • one year ago
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    @joyraheb another way to say infinity or negative infinity is that the limit doesnt exist

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