lexy148
  • lexy148
How do you graph and solve for y= square root x-2 if the x points are 0,-1,-2,1,2
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
is the equation this? \[\Large y = \sqrt{x-2}\] or this?\[\Large y = \sqrt{x}-2\]
lexy148
  • lexy148
the 1st one
lexy148
  • lexy148
@jim_thompson5910

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jim_thompson5910
  • jim_thompson5910
if we replace x with 0, what result do you get \[\Large y = \sqrt{x-2}\] \[\Large y = \sqrt{0-2}\] \[\Large y = ???\]
lexy148
  • lexy148
-2 ?
jim_thompson5910
  • jim_thompson5910
you'll have \[\Large \sqrt{-2}\] BUT you cannot take the square root of a negative number. The result isn't a real number. So the calculator should say NAN or undefined or something
jim_thompson5910
  • jim_thompson5910
did you type in `sqrt(0-2)` or `sqrt(-2)` into your calculator?
lexy148
  • lexy148
yeah thats what it said when i did it in the calculator
jim_thompson5910
  • jim_thompson5910
so because of this error, we don't include x = 0 in the domain
lexy148
  • lexy148
i typed sqrt -2 not 0-2
jim_thompson5910
  • jim_thompson5910
which calculator are you using?
lexy148
  • lexy148
we wouldnt include any negative numbers in sqrt then
jim_thompson5910
  • jim_thompson5910
yes you cannot have negative numbers under the square root eg: \(\Large \sqrt{-1}\) is not allowed
lexy148
  • lexy148
a scientific calculator
jim_thompson5910
  • jim_thompson5910
ok, what happens when you replace x with -1 instead of 0? what result do you get?
lexy148
  • lexy148
ok so i wot put any negatives then thx
lexy148
  • lexy148
i get -3
jim_thompson5910
  • jim_thompson5910
the goal is to have x-2 never be negative so we can force it to be 0 or positive, ie force it to be greater than or equal to 0 \[\Large x-2\ge 0\] solve for x to get \[\Large x\ge 2\] so you are allowed to input values of x that are either 2 or larger than 2
jim_thompson5910
  • jim_thompson5910
you'll find that \[\Large \sqrt{-3}\] isn't a real number. So x = -1 isn't allowed to be an input either
lexy148
  • lexy148
ok i see so only numbers 2 or more, no negatives
jim_thompson5910
  • jim_thompson5910
yep
jim_thompson5910
  • jim_thompson5910
if x = 2, then what is the value of y?
lexy148
  • lexy148
ok thank you and how would you sqrt 0 since 2-2 is 0
jim_thompson5910
  • jim_thompson5910
the square root of 0 is 0
jim_thompson5910
  • jim_thompson5910
your calculator should be able to calculate that if not, then use this calculator http://web2.0calc.com/
lexy148
  • lexy148
nevermind i got it
jim_thompson5910
  • jim_thompson5910
ok one more: if x = 6, then what is the value of y?
lexy148
  • lexy148
thank you for helping me :)
lexy148
  • lexy148
it would be 4
jim_thompson5910
  • jim_thompson5910
the `x-2` part is 4 when x = 6 but I want the value of y \[\Large y = \sqrt{x-2}\] \[\Large y = \sqrt{6-2}\] \[\Large y = \sqrt{4}\] \[\Large y = ??\]
lexy148
  • lexy148
oh srry it would be 2
jim_thompson5910
  • jim_thompson5910
correct, so when x = 6, the value of y is y = 2 that means we have the point (6,2) earlier you found that when x = 2, the value of y was y = 0 so the point (2,0) You make a table of x,y values and plot each ordered pair as a point on the xy grid. Once you have enough points, you can draw a curve through them all to complete the graph

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