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anonymous
 one year ago
@jdoe0001 How do you solve for the equation log x+ log(x3) = 1?
anonymous
 one year ago
@jdoe0001 How do you solve for the equation log x+ log(x3) = 1?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jdoe0001 I know the answer is x= .5(3+sqrt of (9+4e)). I just don't know how the answer key got that answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jdoe0001 actually I just graphed it on my graphing calculator. x=5

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1right... I get something else one sec

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(log(x)+log(x3)=1\implies log[(x)(x3)]=1 \\ \quad \\ log_{{\color{brown}{ 10}}}[(x)(x3)]=1\implies {\color{brown}{ 10}}^1=(x)(x3) \\ \quad \\ 10=x^23x\implies 0=x^23x10 \\ \quad \\ 0=(x5)(x+2)\implies \begin{cases} x=5\\ x=2 \end{cases}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jdoe0001 are you sure about x=2? I plugged 2 in for x and I got "Math ERROR" in the calculator

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1right... logarithms do not take a negative value, is 0 or up so ends up being 5 :)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1but what the answer sheet shows.. looks very different
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