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YumYum247
 one year ago
elp me please!!!!!
YumYum247
 one year ago
elp me please!!!!!

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441153687515:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 Police help me!!! :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 Dan my love come rescue me from this terrible nightmare HUN!!!! :"D

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Any idea?????????????????//

dan815
 one year ago
Best ResponseYou've already chosen the best response.1not sure, the question is a little too vague for me

dan815
 one year ago
Best ResponseYou've already chosen the best response.1does it mean launched by compression of spring or was it just thrown up from equilibriium position

dan815
 one year ago
Best ResponseYou've already chosen the best response.1the spring i take it is not attached to the ground

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0don't worry about the compression or anything, just work with the given variables...

dan815
 one year ago
Best ResponseYou've already chosen the best response.1im trying to determine what is given

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0the g = 9.81m/sec^2, Vi = 2.3m/sec, angle = 78deg

dan815
 one year ago
Best ResponseYou've already chosen the best response.1thats just a projectile problem it has nothing to with spring

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but we have to solve the problem in projectile sense of view....i think.

dan815
 one year ago
Best ResponseYou've already chosen the best response.1oh theres nothing to that then just find V_y

dan815
 one year ago
Best ResponseYou've already chosen the best response.1Vy= sin78* 2.3 m/s a_y= 9.8m/s^2 h=? solve

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0and solve for what????

dan815
 one year ago
Best ResponseYou've already chosen the best response.1height, make sure u understand what is going on

dan815
 one year ago
Best ResponseYou've already chosen the best response.1it should be natural once u understand what is going on

dan815
 one year ago
Best ResponseYou've already chosen the best response.1you have an inital velocity, and ur acceleration is tellng u how much of that velocity u are losing per second

dan815
 one year ago
Best ResponseYou've already chosen the best response.1when the object is at its peak height, its veloicty is 0, so we want to see the time it has been travelling under that acceleration for

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok but i can't see the picture you just posted properly, some of the content is blocked/missing..... :(

dan815
 one year ago
Best ResponseYou've already chosen the best response.1once u get the time its been travelling, you can solve for the actualy distance it travelled in that time

dan815
 one year ago
Best ResponseYou've already chosen the best response.1zoom out to see everything

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok...bit one more thing, there is a formula for this but i'm sure if that would work...let me post it...hold up :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0it looks something like this, le me draw.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441159093595:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0is this right???????????

dan815
 one year ago
Best ResponseYou've already chosen the best response.1im thinking that is from equating the kinetic and potential energy together

dan815
 one year ago
Best ResponseYou've already chosen the best response.1see if both ways gives the same answer if it does then its right

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but what if it doesn't???:O

dan815
 one year ago
Best ResponseYou've already chosen the best response.11/2 m * V_Y^2 = mgh therefore V*sin ^2 (78)/2g = h

dan815
 one year ago
Best ResponseYou've already chosen the best response.1i think you are relying on formulas too much, you have to really understand physics or it wont work

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok what to do for now???? which one tho????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0aight.....!!! Thanks!!! :"D

dan815
 one year ago
Best ResponseYou've already chosen the best response.1i know whats gonna happen both ways, but i want you to explore

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok dear, i'll try to explore. Thank!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0what is the formula for projectile motion, i didn't get it for a sec.... t = Vf +Vi + 1/2(G+t^2)

dan815
 one year ago
Best ResponseYou've already chosen the best response.1u can do this integral too to see if gives u the same distance

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0nooooooooooooooooooooooooooooooooooooooi 2 is not the power.....

dan815
 one year ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=h%3D2.3^2*sin^2%2878%29%2F%282*9.8%29

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.02 multiplies with the sign...i have the formula sheet with me rn.

dan815
 one year ago
Best ResponseYou've already chosen the best response.1i showed u how the formula is derived

dan815
 one year ago
Best ResponseYou've already chosen the best response.1it comes from kinetic1+potenrial1= kinetic2+ potential2

dan815
 one year ago
Best ResponseYou've already chosen the best response.1so in the beginning theres only kinetic as the height is 0 and in the end theres only potential as the velocity in y direction is 0

dan815
 one year ago
Best ResponseYou've already chosen the best response.11/2mv^2=mgh m cancel both sides 1/2 V^2=gh so h=1/2v^2/g

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0yah makes sense......

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0wait what do you mean by Vy tho...vertical velocity O_o

dan815
 one year ago
Best ResponseYou've already chosen the best response.1V_y^2=(Vi*sin 78)^2 =Vi^2 * sin^2 (78)

dan815
 one year ago
Best ResponseYou've already chosen the best response.1yes Vy is the vertical velocity

dan815
 one year ago
Best ResponseYou've already chosen the best response.1Vi is more like the speed or the veloicty in that specific direction

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks a lot.....i mean alot. :)

dan815
 one year ago
Best ResponseYou've already chosen the best response.1okay but u better understand this stuff

dan815
 one year ago
Best ResponseYou've already chosen the best response.1the most important thing is you are able to visualize and work through it in your head

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0yah i'm doing it....it takes time bro, gimme sumtime bro.......

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441162910616:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 i'm stuck!!!! :"(

dan815
 one year ago
Best ResponseYou've already chosen the best response.1what kinda equation is that

dan815
 one year ago
Best ResponseYou've already chosen the best response.1its h(t) = 0 + v_y*t+1/2 * a*t^2

dan815
 one year ago
Best ResponseYou've already chosen the best response.1h(t) is notation for h as a function of t

dan815
 one year ago
Best ResponseYou've already chosen the best response.1Vy= vi*sin (78) t=Vy/9.8 h = 0 + v_y*t+1/2 * a*t^2

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i didn't post the whole thing but i followed your steps.....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Vy= vi*sin (78) t=Vy/9.8 h = 0 + v_y*t+1/2 * a*t^2 if you simplify this you get something i posted.....

dan815
 one year ago
Best ResponseYou've already chosen the best response.1\[V_y= vi*sin (78)\\ t=V_y/9.8 \\ h= 0 + v_y*t+1/2 * a*t^2\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0that's a quadratics expression.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0if you rearrange it.

dan815
 one year ago
Best ResponseYou've already chosen the best response.1its not a quadratic u know what t is already u plug that in

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0omg...i didn't see that....sory....:) let me try again....

dan815
 one year ago
Best ResponseYou've already chosen the best response.1Vi=2.3 Vy=2.3*sin(78) t=Vy/9.8 h=0+Vy*t + 1/2 a*t^2

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0don't say anything just let me take a look at this with my eyes and brain open...

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0yah that works for me....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0h = vertical velocity/2g gives me the right answer....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Anyways don't stress yourself..... go watch a porn to cool off a lil.... :"D i'll get this done on my own now!! :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0btw the example you gave me on wolframe didn't have the time input for T.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441164804108:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 please take a look at this.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i have to use quadratics formula here....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0yes i get that...but what happened at the very last step....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0idk if the website used quadratics formula, or what to get the answe!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0im stuck at the very last part....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441165539159:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0never mind i got it....
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