Write the summation to estimate the area under the curve y = 2x2 + 1 from x = 0 to x = 4 using 4 rectangles and left endpoints.

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- anonymous

- jamiebookeater

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- anonymous

https://gyazo.com/10fefff1c824a71908fefa15fce74b76
It's A, right?
Just making sure I got the right answer, haven't don math in quite some time.

- anonymous

- dinamix

yup its great mate @Ephemera

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## More answers

- anonymous

I got it wrong :(

- zzr0ck3r

@dinamix this is once again why just giving answers can be bad, you don't know the answer is wrong that you gave...

- zzr0ck3r

@Ephemera would you like to learn how to do this?

- dinamix

lol @zzr0ck3r he tell me do that

- anonymous

Of course @zzr0ck3r

- zzr0ck3r

remember we don't start at the beginning of the interval, which here you chose 0.
If we put it into 4 parts, from 0 to 4, we would use the interval [0,1], [1,2], [2,3], and [3,4]. When we take the width of the first interval, we have 1, so we start at 1 not 0. So what is the right answer?

- anonymous

It would be D, right?

- zzr0ck3r

correct

- zzr0ck3r

remember last time, \(x_1=4.5\) not \(4\) even though we were on the interval \([4,6]\).

- dinamix

\[\sum_{i=1}^{4}(2i^2+1) = 3+9+19+33\] @Ephemera i think should be like that

- anonymous

So if it was for example 3 to 5, I'd divide it into 3,3.5,4,4.5?

- zzr0ck3r

once again, @dinamix just giving the answer would not help really, with logic and reasoning you can lead them to the correct answer.

- zzr0ck3r

@Ephemera yes, if they said 4 intervals

- zzr0ck3r

well no, it would be 3.5, 4, 4.5, 5

- zzr0ck3r

this is assuming they want right triangles, which is pretty normal

- zzr0ck3r

but the intervals would be [3,3.5], [3.5,4], [4,4.5], [4.5, 5]

- anonymous

Ok, think I got it
I reset my exam because I got a low grade on the last....can you check over my work @zzr0ck3r?

- dinamix

@zzr0ck3r wow u are good teacher i like u ;)

- zzr0ck3r

Just post questions as you have them, I am not sure how ethical that is...

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