anonymous
  • anonymous
According to the general equation for conditional probability, if P(A^B)= 2/3 and P(B)= 3/4, what is P(A|B)? A. 15/16 B. 24/25 C. 8/9 D. 35/36
Geometry
jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
hint: \[\Large P(A|B) = \frac{P(A \cap B)}{P(B)}\]
anonymous
  • anonymous
Maybe I'm just an idiot? I'm still not getting any of the answers
jim_thompson5910
  • jim_thompson5910
Do you have this so far? \[\Large P(A|B) = \frac{P(A \cap B)}{P(B)}\] \[\Large P(A|B) = \frac{2/3}{3/4}\]

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anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
when you divide 2/3 over 3/4, you're really multiplying 2/3 by 4/3 the second fraction flips and you multiply
anonymous
  • anonymous
the correct answer was 8/9
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
since 2/3 times 4/3 = 8/9

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