anonymous
  • anonymous
Fan and Medal! The expression is shown below:
Mathematics
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anonymous
  • anonymous
Fan and Medal! The expression is shown below:
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
Not sure if it is just me, but I am unable to see your expression : )
anonymous
  • anonymous
\[6a ^{2} - 5ab + 3b - 12\]
anonymous
  • anonymous
now do u see it

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anonymous
  • anonymous
The question: What is the- a)Term b)Constant c)Coefficient
anonymous
  • anonymous
anonymous
  • anonymous
sorry to ask the question late i was helping another friend
jim_thompson5910
  • jim_thompson5910
the terms are separated by a + or a -
jim_thompson5910
  • jim_thompson5910
eg: `x+y-z+w` has four terms: x, y, z, w
jim_thompson5910
  • jim_thompson5910
the constant is any term that doesn't have a variable attached. It's a single fixed number
anonymous
  • anonymous
oh ok so there are 4 terms and 1 constant in the equation
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
but what is coefficient
jim_thompson5910
  • jim_thompson5910
coefficients are the numbers in front of the variables
jim_thompson5910
  • jim_thompson5910
eg: in `7x`, the 7 is the coefficient
anonymous
  • anonymous
so there are 3 coefficients in the equation
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
oh ok but its not done
jim_thompson5910
  • jim_thompson5910
I should have stated that subtraction is the same as adding a negative so something like `1-2` is the same as `1 + (-2)`
jim_thompson5910
  • jim_thompson5910
therefore, \[\Large 6a ^{2} - 5ab + 3b - 12\] is the same as \[\Large 6a ^{2} +(- 5ab) + 3b+( - 12)\]
jim_thompson5910
  • jim_thompson5910
in that second form, we see each term is separated by a +
jim_thompson5910
  • jim_thompson5910
terms are: 6a^2 -5ab 3b -12
anonymous
  • anonymous
ok
jim_thompson5910
  • jim_thompson5910
I'm sure you can see what the constant is for the coefficients, just list the numbers in front of each variable term
anonymous
  • anonymous
constant is 12
jim_thompson5910
  • jim_thompson5910
6, NEGATIVE 5 3
anonymous
  • anonymous
y is it -5?
jim_thompson5910
  • jim_thompson5910
because the term is -5ab the number in front is -5
jim_thompson5910
  • jim_thompson5910
go back to \[\Large 6a ^{2} +(- 5ab) + 3b+( - 12)\]
anonymous
  • anonymous
oh ok now i get it
jim_thompson5910
  • jim_thompson5910
the constant should be -12 for the same reason
anonymous
  • anonymous
constant=-12 coefficient=6, -5, 3 is that correct?
jim_thompson5910
  • jim_thompson5910
yep on all 4
anonymous
  • anonymous
thnx but its not done
jim_thompson5910
  • jim_thompson5910
what else is left?
anonymous
  • anonymous
they said to simplify 2 more expressions by combining like terms
jim_thompson5910
  • jim_thompson5910
which expressions?
anonymous
  • anonymous
ill show u
anonymous
  • anonymous
\[a) 5x-3-3x+6y+4\]
jim_thompson5910
  • jim_thompson5910
what are a pair of like terms that you see?
anonymous
  • anonymous
\[b) -8m ^{2} + 9m - 7m ^{2} + n ^{3}\]
anonymous
  • anonymous
the pair of like terms in the first one?
jim_thompson5910
  • jim_thompson5910
yeah do you see any like terms in the first one?
anonymous
  • anonymous
yes i see two pairs of like terms
jim_thompson5910
  • jim_thompson5910
ok one pair is what?
anonymous
  • anonymous
5x, 3x
jim_thompson5910
  • jim_thompson5910
more like 5x and -3x, but you have the right idea
jim_thompson5910
  • jim_thompson5910
they would combine to ???
anonymous
  • anonymous
u mean add?
jim_thompson5910
  • jim_thompson5910
yeah, 5x + (-3x) = ??
anonymous
  • anonymous
it's 2x
jim_thompson5910
  • jim_thompson5910
yep
jim_thompson5910
  • jim_thompson5910
you'll do the same for the other pair of like terms
anonymous
  • anonymous
what is the other pair
jim_thompson5910
  • jim_thompson5910
you tell me
jim_thompson5910
  • jim_thompson5910
look for any terms that have something in common
jim_thompson5910
  • jim_thompson5910
for the 5x and -3x, they had an x in common
anonymous
  • anonymous
is it -3, 4
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
yay
jim_thompson5910
  • jim_thompson5910
they add to what?
anonymous
  • anonymous
is it 1?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
and then?
jim_thompson5910
  • jim_thompson5910
notice how there is only one y term, so there are no like terms for the y terms all of this means `5x−3−3x+6y+4` simplifies to `2x+6y+1`
anonymous
  • anonymous
oh ok so 2x+6y+1 is the answer or should i evaluate the expression
jim_thompson5910
  • jim_thompson5910
if you knew the value of x and y, you could evaluate to get a single number
jim_thompson5910
  • jim_thompson5910
but they didn't provide values for x and y
anonymous
  • anonymous
So for now 2x+6y+1 is the answer, right?
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
Ok thank u very much u dont have to explain the 2 expression because its almost the same as the first expression
jim_thompson5910
  • jim_thompson5910
yeah it's very similar so you shouldn't have too much trouble with it
anonymous
  • anonymous
thats it for today thank u very much dude ur the best
jim_thompson5910
  • jim_thompson5910
just keep in mind that terms with \(\Large m^2\) are NOT like terms with \(\Large m^3\) they both have m, but different exponents makes them different and unlike terms
jim_thompson5910
  • jim_thompson5910
same with m and m^2
anonymous
  • anonymous
oh ok thanks for the tips i fanned and i gave u a medal for all three questions thank u very much i will ask u whenever i have a question from now on.

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