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anonymous

  • one year ago

Fan and Medal! The expression is shown below:

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  1. anonymous
    • one year ago
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    Not sure if it is just me, but I am unable to see your expression : )

  2. anonymous
    • one year ago
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    \[6a ^{2} - 5ab + 3b - 12\]

  3. anonymous
    • one year ago
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    now do u see it

  4. anonymous
    • one year ago
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    The question: What is the- a)Term b)Constant c)Coefficient

  5. anonymous
    • one year ago
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    @jim_thompson5910

  6. anonymous
    • one year ago
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    sorry to ask the question late i was helping another friend

  7. jim_thompson5910
    • one year ago
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    the terms are separated by a + or a -

  8. jim_thompson5910
    • one year ago
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    eg: `x+y-z+w` has four terms: x, y, z, w

  9. jim_thompson5910
    • one year ago
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    the constant is any term that doesn't have a variable attached. It's a single fixed number

  10. anonymous
    • one year ago
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    oh ok so there are 4 terms and 1 constant in the equation

  11. jim_thompson5910
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    but what is coefficient

  13. jim_thompson5910
    • one year ago
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    coefficients are the numbers in front of the variables

  14. jim_thompson5910
    • one year ago
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    eg: in `7x`, the 7 is the coefficient

  15. anonymous
    • one year ago
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    so there are 3 coefficients in the equation

  16. jim_thompson5910
    • one year ago
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    yes

  17. anonymous
    • one year ago
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    oh ok but its not done

  18. jim_thompson5910
    • one year ago
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    I should have stated that subtraction is the same as adding a negative so something like `1-2` is the same as `1 + (-2)`

  19. jim_thompson5910
    • one year ago
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    therefore, \[\Large 6a ^{2} - 5ab + 3b - 12\] is the same as \[\Large 6a ^{2} +(- 5ab) + 3b+( - 12)\]

  20. jim_thompson5910
    • one year ago
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    in that second form, we see each term is separated by a +

  21. jim_thompson5910
    • one year ago
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    terms are: 6a^2 -5ab 3b -12

  22. anonymous
    • one year ago
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    ok

  23. jim_thompson5910
    • one year ago
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    I'm sure you can see what the constant is for the coefficients, just list the numbers in front of each variable term

  24. anonymous
    • one year ago
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    constant is 12

  25. jim_thompson5910
    • one year ago
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    6, NEGATIVE 5 3

  26. anonymous
    • one year ago
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    y is it -5?

  27. jim_thompson5910
    • one year ago
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    because the term is -5ab the number in front is -5

  28. jim_thompson5910
    • one year ago
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    go back to \[\Large 6a ^{2} +(- 5ab) + 3b+( - 12)\]

  29. anonymous
    • one year ago
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    oh ok now i get it

  30. jim_thompson5910
    • one year ago
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    the constant should be -12 for the same reason

  31. anonymous
    • one year ago
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    constant=-12 coefficient=6, -5, 3 is that correct?

  32. jim_thompson5910
    • one year ago
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    yep on all 4

  33. anonymous
    • one year ago
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    thnx but its not done

  34. jim_thompson5910
    • one year ago
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    what else is left?

  35. anonymous
    • one year ago
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    they said to simplify 2 more expressions by combining like terms

  36. jim_thompson5910
    • one year ago
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    which expressions?

  37. anonymous
    • one year ago
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    ill show u

  38. anonymous
    • one year ago
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    \[a) 5x-3-3x+6y+4\]

  39. jim_thompson5910
    • one year ago
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    what are a pair of like terms that you see?

  40. anonymous
    • one year ago
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    \[b) -8m ^{2} + 9m - 7m ^{2} + n ^{3}\]

  41. anonymous
    • one year ago
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    the pair of like terms in the first one?

  42. jim_thompson5910
    • one year ago
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    yeah do you see any like terms in the first one?

  43. anonymous
    • one year ago
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    yes i see two pairs of like terms

  44. jim_thompson5910
    • one year ago
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    ok one pair is what?

  45. anonymous
    • one year ago
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    5x, 3x

  46. jim_thompson5910
    • one year ago
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    more like 5x and -3x, but you have the right idea

  47. jim_thompson5910
    • one year ago
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    they would combine to ???

  48. anonymous
    • one year ago
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    u mean add?

  49. jim_thompson5910
    • one year ago
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    yeah, 5x + (-3x) = ??

  50. anonymous
    • one year ago
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    it's 2x

  51. jim_thompson5910
    • one year ago
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    yep

  52. jim_thompson5910
    • one year ago
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    you'll do the same for the other pair of like terms

  53. anonymous
    • one year ago
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    what is the other pair

  54. jim_thompson5910
    • one year ago
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    you tell me

  55. jim_thompson5910
    • one year ago
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    look for any terms that have something in common

  56. jim_thompson5910
    • one year ago
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    for the 5x and -3x, they had an x in common

  57. anonymous
    • one year ago
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    is it -3, 4

  58. jim_thompson5910
    • one year ago
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    yes

  59. anonymous
    • one year ago
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    yay

  60. jim_thompson5910
    • one year ago
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    they add to what?

  61. anonymous
    • one year ago
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    is it 1?

  62. jim_thompson5910
    • one year ago
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    yes

  63. anonymous
    • one year ago
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    and then?

  64. jim_thompson5910
    • one year ago
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    notice how there is only one y term, so there are no like terms for the y terms all of this means `5x−3−3x+6y+4` simplifies to `2x+6y+1`

  65. anonymous
    • one year ago
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    oh ok so 2x+6y+1 is the answer or should i evaluate the expression

  66. jim_thompson5910
    • one year ago
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    if you knew the value of x and y, you could evaluate to get a single number

  67. jim_thompson5910
    • one year ago
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    but they didn't provide values for x and y

  68. anonymous
    • one year ago
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    So for now 2x+6y+1 is the answer, right?

  69. jim_thompson5910
    • one year ago
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    yes

  70. anonymous
    • one year ago
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    Ok thank u very much u dont have to explain the 2 expression because its almost the same as the first expression

  71. jim_thompson5910
    • one year ago
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    yeah it's very similar so you shouldn't have too much trouble with it

  72. anonymous
    • one year ago
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    thats it for today thank u very much dude ur the best

  73. jim_thompson5910
    • one year ago
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    just keep in mind that terms with \(\Large m^2\) are NOT like terms with \(\Large m^3\) they both have m, but different exponents makes them different and unlike terms

  74. jim_thompson5910
    • one year ago
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    same with m and m^2

  75. anonymous
    • one year ago
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    oh ok thanks for the tips i fanned and i gave u a medal for all three questions thank u very much i will ask u whenever i have a question from now on.

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